Quick PyQt4 connect question

[robertogoberto]

I don't have access to my code at the moment, but from memory it goes something like

class GLWidget(QGLWidget):
	def __init__(self, parent=None):
		QGLWidget.__init__(self, QGLFormat(QGL.SampleBuffers), parent)
		self.connect(self, SIGNAL('clicked()'), self.test) 
	def test():
		print "wee"

class GLWidget(QGLWidget):
	def __init__(self, parent=None):
		QGLWidget.__init__(self, QGLFormat(QGL.SampleBuffers), parent)
		self.connect(self, SIGNAL('clicked()'), self.test) 
	def test():
		print "wee"

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my main window is simply this widget, the problem is connect doesn't seem to have any effect -- it doesn't complain about anything, it just doesn't do anything. Not sure what the problem is. My understanding is QObject -> QWidget -> QGLWidget, since I inherit from QGLWidget I should be able to use self as the first parameter, am I wrong?

if you see any syntax errors / typos keep in mind I'm reproducing this from memory, everything executes error free. I can post the actual code when I have a chance.

[robertogoberto]

class GLWidget(QGLWidget):
  width = 1024
  height = 768
  def testing(self):
	print "working"
  def __init__(self, width, height, parent=None):
	QGLWidget.__init__(self, QGLFormat(QGL.SampleBuffers), parent)
	self.connect(self, SIGNAL('clicked()'), self.testing)
	self.width = width
	self.height = height

class GLWidget(QGLWidget):
  width = 1024
  height = 768
  def testing(self):
	print "working"
  def __init__(self, width, height, parent=None):
	QGLWidget.__init__(self, QGLFormat(QGL.SampleBuffers), parent)
	self.connect(self, SIGNAL('clicked()'), self.testing)
	self.width = width
	self.height = height

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app = QApplication(sys.argv)
test = GLWidget(1024,768)
test.show()
sys.exit(app.exec_())

app = QApplication(sys.argv)
test = GLWidget(1024,768)
test.show()
sys.exit(app.exec_())

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There is actual (relevant) code. Runs, displays, no errors, but no connect.