How to parse this xml file?

[Gokulnathvc]

I have found the solution>>. Thanks for your help.

for ( node = docElem.firstChild();!node.isNull();node = node.nextSibling()) {
 
   while(node.toElement().tagName() == "folder")
   {
       firmFolder += node.toElement().attribute("name");
       firmFolder += "/";
       node = node.firstChild();
   }
   while(node.toElement().tagName() == "file")
   {
       firmFiles += node.toElement().attribute("name");
       firmFiles += " ";
       saveNode = node;
       node = node.nextSibling();
   }
 
    //node = docElem.firstChild();
   node = saveNode.parentNode();
 
   while(node.parentNode().toElement().tagName() != "package"){
    node = node.parentNode();
    }
}

for ( node = docElem.firstChild();!node.isNull();node = node.nextSibling()) {

   while(node.toElement().tagName() == "folder")
   {
       firmFolder += node.toElement().attribute("name");
       firmFolder += "/";
       node = node.firstChild();
   }
   while(node.toElement().tagName() == "file")
   {
       firmFiles += node.toElement().attribute("name");
       firmFiles += " ";
       saveNode = node;
       node = node.nextSibling();
   }

    //node = docElem.firstChild();
   node = saveNode.parentNode();

   while(node.parentNode().toElement().tagName() != "package"){
    node = node.parentNode();
    }
}

To copy to clipboard, switch view to plain text mode 

[wysota]

That's a really bad solution.

Here is a better one:

Implement the following function called "getPath"
1. Go to first child element with tag "folder"
2. If there is no such tag, go to first child element with tag "file", otherwise skip to step 6
3. If there is no such tag, return an empty list
4. Add the name of the file to a list
5. Go to next sibling of the tag that is also tagged "file", add it to the list and keep doing that until you run out of "file" tags. Then return a list of files found.
6. Call getPath on the folder tag.
7. For each string returned by getPath, prepend it with the folder name just found and a directory separator
8. Repeat for all sibling "folder" tags
9. Return a list of found entries.

If you call getPath on the parent node of the "folder" nodes, you'll get a complete list of entries in the package.

[Gokulnathvc]

Could you modify my code and describe how it should be?

[wysota]

No, I would have to discard your code and write a new one from scratch. And if I wanted to, I would have already done that. Learn your lesson and do it yourself.