codeverse
11th August 2010, 15:46
Hi everybody!
I have a problem that i can't resolve.
In a class I created a SIGNAL void newMessage(QTcpSocket*,QString) that when is emitted, it calls a method that send to QTcpSocket* the QString message. I happened to observe, however, that if you emit two newMessage into the same method, the two strings passed to the respective SIGNAL are merged into a unique parameter of slot.
So the slot is called once time only.
Why does this happen? :confused: Can it be overcome, forcing the separation of the two signals?
Thanks in advance.
EDIT: I'm sorry, i did a mistake checking the debug output.
I have a problem that i can't resolve.
In a class I created a SIGNAL void newMessage(QTcpSocket*,QString) that when is emitted, it calls a method that send to QTcpSocket* the QString message. I happened to observe, however, that if you emit two newMessage into the same method, the two strings passed to the respective SIGNAL are merged into a unique parameter of slot.
So the slot is called once time only.
Why does this happen? :confused: Can it be overcome, forcing the separation of the two signals?
Thanks in advance.
EDIT: I'm sorry, i did a mistake checking the debug output.