QPainter drawArc question

[kloopa]

Hi. I'm trying to use QPainter drawArc(const QRectF & rectangle, int startAngle, int spanAngle) for arc drawing.
And have a problem with it.
I have a coordinates of 3 arc points A, B, C.
A - arc start point
B - arc end point
C - arc center with known radius (10).

Question. How to calculate rectangle, startAngle and spanAngle for this arc?

11595

[ChrisW67]

The rectangle is the rectangle that would contain the entire circle if drawn completely, and you get the angles with basic trigonometry:

QPointF const A(6.31, 5.773);
QPointF const B(20.53, 19.836);
QPointF const C(13.42, 12.805);
double const radius(10.0);

QRectF const r(C.x() - radius, C.y() - radius, radius * 2, radius * 2);
double const startAngle = 16 * atan2(A.y() - C.y(), A.x() - C.x()) * 180.0 / M_PI;
double const endAngle = 16 * atan2(B.y() - C.y(), B.x() - C.x()) * 180.0 / M_PI;
double const spanAngle = endAngle - startAngle;

QImage img(500, 500, QImage::Format_RGB32);
img.fill(Qt::white);
QPainter p(&img);
p.scale(10.0, 10.0);
p.setPen(Qt::red);
p.drawRect(r);
p.setPen(Qt::black);
p.drawArc(r, startAngle, spanAngle);
p.end();
img.save("test.png");

You might need to tweak this for some cases

[kloopa]

Thank you for reply! It works.
How to draw clockwise and counter-clockwise? (using drawArc and arcTo)
How to calculate sweepLength for QPainterPath.arcTo?

[ChrisW67]

Experiment with swapping A and B and changing the sign of the spanAngle.
If you want to draw the shortest arc between two points and spanAngle is greater than 180 degrees (+ve or -ve) then you need to add/subtract 360 degrees to the spanAngle (changes the sign and hence drawing direction).

The angle for arcTo is calculated the same way without the 16 multiplier used by QPainter.

[kloopa]

ChrisW67, Can you recommend me how to draw all known arcs :) using your code? Arcs may be more than (+-)180, full circle(360). I tried top play with code myself many times, but without result.

For example, i'm reading file with coordinates:

START: X143.178 Y82.461
LINE-TO: X13.178 Y82.461
ARC-TO[Clockwise]: X2.278 Y93.361 cX13.178 cY93.361
LINE-TO: X2.278 Y151.361
ARC-TO[Clockwise]: X13.178 Y162.261 cX13.178 cY151.361
LINE-TO: X143.178 Y162.261
ARC-TO[Clockwise]: X154.078 Y151.361 cX143.178 cY151.361

Where cX, cY arc center coordinates. Arcs may drawing counter clockwise.

I want to see like this:

11631

Now i see:

11632

[ChrisW67]

Everything you need is in my earlier post http://www.qtcentre.org/threads/64705-QPainter-drawArc-question?p=286095#post286095
Read the docs for QPainter::drawArc() to understand how span angle determines the drawing direction.

[kloopa]

For clockwise / counter-clockwise drawing question solved.
But arcs still incorrect. I think problem when calculating angles. Because angles may be + or -.
My program reading coordinates form TXT file (file generated by other software from DXF format, where 0 degree at 12 o'clock).

Part of my code (Python3):


def arcAngles(self, a, b, c):
startAngle = 16*atan2(a.y() - c.y(), a.x() - c.x())*180 / pi
endAngle = 16*atan2(b.y() - c.y(), b.x() - c.x())*180 / pi

spanAngle = abs(endAngle) - abs(startAngle)

#Clocksiwe
if self.direction == -1:
if spanAngle > 0:
spanAngle = -spanAngle

print("START: " + str(startAngle / 16) + "\nEND: " + str(endAngle / 16) + "\nSPAN: " + str(spanAngle / 16))
angles = {'start': startAngle, 'end': endAngle, 'span': spanAngle}

return angles


Result:



=====1st Arc====
START: -90.0
END: 180.0
SPAN: -90.0
LastPoint: PyQt5.QtCore.QPointF(13.178, 82.461)
EndPoint: PyQt5.QtCore.QPointF(2.278, 93.361)

=====2nd Arc====
START: 180.0
END: 90.0
SPAN: -90.0
LastPoint: PyQt5.QtCore.QPointF(2.278, 151.361)
EndPoint: PyQt5.QtCore.QPointF(13.178, 162.261)

=====3rd Arc====
START: 90.0
END: 0.0
SPAN: -90.0
LastPoint: PyQt5.QtCore.QPointF(143.178, 162.261)
EndPoint: PyQt5.QtCore.QPointF(154.078, 151.361)


Drawing result:
11633

I tried to solve this by manipulation with offset (90 degree), but still not solved.

Substracting offset from angles:



offset = 90*16

if startAngle < 0:
startAngle -= -offset
else:
startAngle -= offset

if endAngle < 0:
endAngle -= -offset
else:
endAngle -= offset


When substract offset from angles i see:

11636

Add offset to angles:



offset = 90*16

if startAngle < 0:
startAngle += -offset
else:
startAngle += offset

if endAngle < 0:
endAngle += -offset
else:
endAngle += offset


When adding offset to angles i see:

11637