View Full Version : Available Screen Problem
December
3rd July 2007, 16:11
Hi All,
I am having a problem placing a window just above the taskbar, and detecting if there is a taskbar at the top (normal for Gnome and OSX, not usually on KDE and Windows).
For some reason both..
QApplication::desktop()->screenGeometry() and
QApplication::desktop()->availableGeometry()
..are returning exactly the same, the full size of the screen.
Any ideas what I might be doing wrong?
Thanks
guilugi
3rd July 2007, 16:55
There was a similar thread a while ago :
Don't know if it helps.
http://www.qtcentre.org/forum/f-qt-programming-2/t-how-can-i-get-the-systray-height--6020.html/?highlight=systray
December
4th July 2007, 15:33
Thanks for the post, but what is being suggested in the thread is what I am already doing.
The problem is that availableGeometry is returning exatly the same as screenGeometry.
guilugi
4th July 2007, 16:06
Well, maybe I'm silly on this one, but does QDesktopWidget::availableGeometry() is exactly the same as QApplication::desktop()->availableGeometry() ?
Another (ugly) hint, would be to deduce the systray height from the QSystemTrayIcon geometry (which is available)
My 2 cents..
December
4th July 2007, 16:53
From the documentation:
QDesktopWidget::QDesktopWidget ()
Creates the desktop widget.
If the system supports a virtual desktop, this widget will have the size of the virtual desktop; otherwise this widget will have the size of the primary screen.
Instead of using QDesktopWidget directly, use QApplication::desktop().
This seems to imply the way to use QDesktopWidget is to get it return from QApplication.
A quick test creating a new Desktop widget also had the same result. For some reason it availableGeometry is ignoring any taskbars on the screen totally.
guilugi
4th July 2007, 17:01
Maybe you should suggest something about this feature to Trolls, then ;-)
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