PDA

View Full Version : Hasn't QTableWidget an "activated" signal?



Morea
19th September 2007, 00:04
Here is the code. ui.tableWidget is a pointer to a tableWidget and I've successfully added items to it. But the following doesn't work



disconnect(ui.tableWidget,SIGNAL(activated(QModelI ndex&)));
connect(ui.tableWidget,SIGNAL(activated(QModelInde x&)),this,SLOT(tableKeyPressSLOT(QModelIndex&)));


I get

Object::disconnect: No such signal QTableWidget::activated(QModelIndex&)
Object::disconnect: (sender name: 'MainWindow')
Object::disconnect: (receiver name: 'tableWidget')
Object::connect: No such signal QTableWidget::activated(QModelIndex&)
Object::connect: (sender name: 'tableWidget')
Object::connect: (receiver name: 'MainWindow')

If I read the manual correctly, activated is a signal in the QTableWidget class.

wysota
19th September 2007, 01:53
Actually it's "activated(const QModelIndex&)".