Repainting/Refreshing Layout after one QWidget * has changed

Hi,

I have a layout filled with 2 widgets.
I would like to replace one of the widgets of the layout using a signal/slot mechanism.

What do I need to do so that the layout is repainted/refreshed using the new widget after the widget has been changed ?

Code:

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DriverView::DriverView( QWidget* parent ) :
        QWidget( parent )
{
    // Title
    title = new TitleFrame(this,"Actual Driver");
    // Body
    body = driverFactory()->driverUserInterface(driverFactory()->currentDriver());
 
    // Layout
    QVBoxLayout *mainLayout = new QVBoxLayout;
    mainLayout->addWidget(title);
    mainLayout->addWidget(body);
    mainLayout->setContentsMargins (0, 0, 0, 0); 
    setLayout(mainLayout);
 
    connect(driverFactory(),SIGNAL(driverHasChanged()), this, SLOT(refreshDriverView()));
}

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Code:

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void 
DriverView::refreshDriverView() {
    body = driverFactory()->driverUserInterface(driverFactory()->currentDriver());
    // repaint(); doesn't work
    // update(); doesn't work
}

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You only change the body variable. Qt still has a pointer to the old widget. See QStackedWidget and QStackedLayout. Also don't forget to show the new widget.

Is there a way to tell QT to use the pointer on the new widget instead of the pointer of the old one ?

Alternatively is it possible to delete the entire layout and create a new one ?

This seems to work:

Code:

---

void 
DriverView::refreshDriverView() {
    body->hide();
    mainLayout->removeWidget(body);
    body = driverFactory()->driverUserInterface(driverFactory()->currentDriver());
    mainLayout->addWidget(body);
    body->show();
}

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Is there anything that speeks against this ?

Quote:

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Originally Posted by schall_l

Is there anything that speeks against this ?

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Where do you get rid of unused widgets?