QTcpServer : retrieve the requested URL

Hi there!

I have developped a server, its address is 127.0.0.1:4242 ; I'm using QTcpServer, and QTcpSocket (to send the answer).

I would like to be able to know what is the requested URL. :(

For example, if I type this in Firefox :

Code:

---

http://127.0.0.1:4242/directory1/test/

---

how can I know that firefox wants to access /directory/test/ ?

I tried localAddress(), but it only returns 127.0.0.1



I really need your help guys ! :(

Hi there!

You need a HTTP-Server for that.

Have a look at: http://doc.trolltech.com/solutions/4...le-server.html

HIH

Johannes

Thank you but I can't figure out what is the function that gives the requested address in your example :confused:

Well.. you need to parse the get command..

http://en.wikipedia.org/wiki/Hyperte...xample_session

Code:

---

QStringList tokens = QString(socket->readLine()).split(QRegExp("[ \r\n][ \r\n]*"));
     if (tokens[0] == "GET") {

---

tokens[1] should be the requested url.

Sorry for not having pointed that out .. Maybe you just need to search for a more complete HTTP Server using google?

Johannes

Perfect !
Thank you very much ! :cool: