Custom plugin for a layout

Is it possible to create a designer plugin for a custom "widget" that does not derive from QWidget? I have a custom layout class that derives from QBoxLayout, and I would like to display it in designer, just like I do with my custom widgets. The problem is that the createWidget() method of the plugin class returns a QWidget*, but the layout does not derive from QWidget.

Thanks,
Cristian

Quote:

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Originally Posted by cocheci

Is it possible to create a designer plugin for a custom "widget" that does not derive from QWidget? I have a custom layout class that derives from QBoxLayout, and I would like to display it in designer, just like I do with my custom widgets. The problem is that the createWidget() method of the plugin class returns a QWidget*, but the layout does not derive from QWidget.

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No, it has to be QWidget. You can cheat a little though and return an empty QWidget just with your layout set (just remember the widget has to be marked as a container).

I don't remember the exact syntax, but it's something like this:

Code:

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QWidget * plugin::createWidget(const QString &feature, QWidget *p){
 if(feature=="xxx"){
    QWidget *w = new QWidget(p);
    MyLayout *l = new MyLayout(p);
    w->setLayout(l);
    return w;
  }
}

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Quote:

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Originally Posted by wysota

No, it has to be QWidget. You can cheat a little though and return an empty QWidget just with your layout set (just remember the widget has to be marked as a container).

I don't remember the exact syntax, but it's something like this:

Code:

---

QWidget * plugin::createWidget(const QString &feature, QWidget *p){
 if(feature=="xxx"){
    QWidget *w = new QWidget(p);
    MyLayout *l = new MyLayout(p);
    w->setLayout(l);
    return w;
  }
}

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This worked, thank you!
Cristian