need to run only one instance of application

Hello,

before I worked with this delphi code:

Code:

---

function FileInstanceCheck(var mutex : THandle):boolean;
var
        mutexName : array [0..7] of char;
begin
   Result:=false;
   StrPCopy(mutexName ,'anyname');
   mutex := openmutex ( MUTEX_ALL_ACCESS, False, mutexName )  ;
   If ((mutex <> 0) ) then
   begin
    MessageBeep($FFFFFFFF);
    //MyMsgDialog('The application is already running.');
    exit;
   end;
   mutex := createmutex ( nil , true, mutexName);
   Result:=true;
end;

---

now, I look forward to a straightforward Qt code.

regards
navid

Please refer following link.
http://qt.nokia.com/products/appdev/...gleapplication

thanks, i will try new open source one

Quote:

---

Originally Posted by navid

please provide me with a free code

---

Respected Sir,
Would you like to have the code with a double scoop of choco chips icecream?

Quote:

---

Originally Posted by navid

thanks, i will try new open source one

---

http://qt.nokia.com/products/appdev/...leapplication/

There is another possibility to do what you want:

Quote:

---

QLocalSocket socket;
socket.connectToServer(serverName);
if (socket.waitForConnected(500)) return;

m_localServer = new QLocalServer(this);
connect(m_localServer, SIGNAL(newConnection()), this, SLOT(newLocalSocketConnection()));
m_localServer->listen(serverName);

---

a) You create a QLocalSocket and connect to the server specified by the serverName;
b) Create a QLocalServer and listen for the connections;
c) before starting the application check how much connections you are listening already ... if there is at least one that means you have opened an application and you shouldn't let another one to open