Time out for a QProcess?

hi all.
I have a program(called Mother_Program) and this program calls other program( called Tesst.exe), and for 3 seconds the Tesst.exe must close, if Tesst.exe takes bigger than 3 seconds, Mother_Programm have raise time out. But i don't how to code the timeout function?
thanks
This is my code

Code:

---

#include <QtCore/QCoreApplication>
#include<QProcess>
#include<stdio.h>
class TIMEOUT{
public:
signals:
    void timeout();
};
void TIMEOUT::timeout(){
//Help me code there. Thanks
}
 
int main(int argc, char *argv[])
{
    QCoreApplication a(argc, argv);
QProcess proc;
TIMEOUT timeout;
QObject::connect(&proc, SIGNAL(timeout.timeout()),&a, SLOT(quit()));
proc.execute("C:\\Tesst.exe");
printf("Hello");
proc.waitForFinished(1000);
    return a.exec();
}

---

thanks

use QProcess::waitForFinished with a 3 sec timeout and check the condition of QProcess weather it has finished or not. then you can emit the appropriate signal.

as you see above i have

Code:

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proc.waitForFinished(1000);

---

and how to know that it has finihed or not while it still runnign in another process
but seem that it does not work well

first of all, your connect() statement is incorrect. secondly your approach to the problem is incorrect.

Quote:

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Originally Posted by nish

first of all, your connect() statement is incorrect. secondly your approach to the problem is incorrect.

---

Thanks
Could you show my errors to me?

Quote:

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Originally Posted by nthung

Thanks
Could you show my errors to me?

---

Thanks
I think that when Tesst.exe take more than 1 second, althought that Tesst.exe still running, but Mother_Programwill pass proc.waitForFinished(1000);
Do you think that?
Thanks

Here is an incomplete list of things to consider (look for the comments):

Code:

---

#include <QtCore/QCoreApplication>
#include<QProcess>
#include<stdio.h>
class TIMEOUT{ // << needs to be derived from QObject to contain signals/slots
// << needs the Q_OBJECT macro for the same reason
public:
signals:
    void timeout();  // << this should be a slot, not a signal
};
void TIMEOUT::timeout(){
//Help me code there. Thanks
// << You will need code to terminate the process
}
 
int main(int argc, char *argv[])
{
    QCoreApplication a(argc, argv);
QProcess proc;
TIMEOUT timeout;
QObject::connect(&proc, SIGNAL(timeout.timeout()),&a, SLOT(quit())); // << QProcess has no signal called timeout.timeout()
proc.execute("C:\\Tesst.exe");  // << this executes the program and waits for it to finish
printf("Hello");  // << Hi!
proc.waitForFinished(1000);  // << pointless, the Tesst program has finished before it can get here
    return a.exec(); 
}

---

To start and time out and terminate a sub process you will have to read:

• Signal & Slots
• QProcess::start(), QProcess::kill(), and all the signals

The structure of your program will change quite a lot (or it won't compile)

thank you so much