MacOS Key_F9 becomes Key_8

Hi people!!!

I have a strange behaviour on MacOS X... On my QAction I have set the following

Code:

---

QAction my1Action = new QAction(this);
my1Action->setShortcut(Qt::Key_F9);
my1Action->setText(tr("My 1st action"));
connect(...)
 
QAction my2Action = new QAction(this);
my2Action->setShortcut(QSequence(Qt::SHIFT + Qt::Key_F9));
my2Action->setText(tr("My 2nd action"));
connect(...)

---

Now... why in my menu do I see the following???
(in the menu, F9 is replaced by a 8)...
Attachment 7542

This happens only on Mac, on windows it works pretty well.

Thanks for any hint...

That's odd...
Does it happen for all keys or only F9?

Hi Spitfire.

Thank you for taking the time to answer me :D
Only with F9... I saw on Mac documentation that Function keys from F9 to F12 are used by OSX to handle Dashbord and windows behaviour... I'm quite sure it is related...
Anyway, I could not find out why it uses the 8...

Hi,

Code:

---

#include <QtGui>
 
int main(int argc, char *argv[])
{
    QApplication a(argc, argv);
 
    QMainWindow w;
 
    QAction* my1Action = new QAction(&w);
    my1Action->setShortcut(Qt::Key_F9);
    my1Action->setText("My 1st action");
 
    QAction* my2Action = new QAction(&w);
    my2Action->setShortcut(QKeySequence(Qt::SHIFT + Qt::Key_F9));
    my2Action->setText("My 2nd action");
 
    QMenu m;
    m.addAction(my1Action);
    m.addAction(my2Action);
    m.setTitle("test");
    w.menuBar()->addMenu(&m);
 
    w.show();
 
    return a.exec();
}

---

works just fine on my MacOSX 10.6.8 (MacBook Pro).

Ok... that means it's a misconfiguration on my mac...

Thank you very much!

---

Added after 9 minutes:

I put up a Brand new Mac OS 10.7.3 machine... Installed Xcode and QT and...
there it is... F9 is replaced with an 8...
I'll investigate further, but I think this problem starts with the 10.7.3 update released in march 2012...