Avoiding Q_DECLARE_METATYPE

Hi,

I have a standard C++ object.

Code:

---

class A
{
 // ...
};

---

I can't (and I don't want to) define it as a Qt type.

Though, I still like to put it in the model (QStandardItemModel for instance).

So far, I was able to but a raw pointer into the model with the very ugly following code :

Code:

---

// I have
const A &a = ; //...
 
// Writing
        item->setData(
                    qVariantFromValue(
                        reinterpret_cast<void*>(
                            const_cast<A*>(
                                &a
                                )
                            )
                        ),
                    Role
                    );
 
// Reading
        const A &a = *reinterpret_cast<A*>(
                    const_cast<const void*>(
                        item->data(Role).value<void*>()
                        )
                    );

---

How bad is this ?

Anything better ?

Thanks !

PS0 : I read the method with Q_DECLARE_METATYPE.
PS1 : I could always create an intermediate Qt type which would embed my non Qt type...but that seems heavy too.

Would this look simpler

Code:

---

...
QStandardItem item;
...
const A a0;
...
item.setData(reinterpret_cast<unsigned int>(&a), Role);
...
const A & a1 = *reinterpret_cast<const A*>(item.data(Role).toUInt());   
//or
const A & a2 = *reinterpret_cast<const A*>(modelIndex.data(Role).toUInt());  
...

---

Okay for the casts factorisation, and the "toUInt()" simplification.

What the difference between the "void*" and the "unsigned int" casts ?

I suppose most machines will accept them indifferently. Though, I might have to mind about portability. So I guess the safest move id to go with "void*" ? But "unsigned int" simplifies a lot :D

Why avoid the macro and invent work that can be hidden in the QVariant class for you?

What if I have no control over the type ie the type is defined in a library ? I have to create a header include the library and including the Q_DECLARE_METATYPE and I will link that file when I need the meta type ? Fair enough.

By the way, can we guard Q_DECLARE_METATYPE through Qt ?

Quote:

---

Originally Posted by moijhd

What if I have no control over the type ie the type is defined in a library ?

---

If the type has a default constructor and can be copied then you can store it in a QVariant.
If the class does not meet the requirements then you can store a pointer (const or not) in a QVariant.
You need to arrange somewhere that Q_DECLARE_METATYPE() is invoked before you try to use the 3rd party type in a QVariant.

Code:

---

#include <QtCore>
 
// From some library header
class AClass {
public:
    AClass() { }
    ~AClass() { }
    AClass(const AClass &other) { }
};
 
class BClass {
public:
    BClass() { }
    ~BClass() { }
private:
    BClass(const BClass &other) { } // cannot be copied
};
// end of header
 
Q_DECLARE_METATYPE(AClass)
Q_DECLARE_METATYPE(const BClass*)
 
int main(int argc, char **argv) {
    QCoreApplication app(argc, argv);
 
    AClass aa;
    QVariant av = QVariant::fromValue(aa);
    // later
    AClass ar = av.value<AClass>();
 
    const BClass bb;
    QVariant bv = QVariant::fromValue(&bb);
    // later
    const BClass *br = bv.value<const BClass*>();
 
    return 0;
}

---

Quote:

---

By the way, can we guard Q_DECLARE_METATYPE through Qt ?

---

I have no idea what this means.

Ok thanks !

Guard for me :D

Code:

---

#ifndef Q_DECLARE_METATYPE_AClass
#define Q_DECLARE_METATYPE_AClass
Q_DECLARE_METATYPE(AClass)
#endif

---