QProcess : force cout to be sent

Hello :)

I've two application A and B.
The first one - A - creates a QProcess in order to call the second one - B -.
The first one - A - listen the second one - B -, using readyRead() signal.

So, our B application send data to A in a loop :

Code:

---

int i = 0;
while (i<10)
{
	std::cout << i << std::endl;
	i++;
}

---

The A application detects that data is ready read, and display it :

Code:

---

QString message = "";	
	message.append(myProcess->readAllStandardOutput());
	std::cout << "." << message.toStdString() << "." << std::endl;

---

And the message is :

Quote:

---

.0
1
2
3
4
5
6
7
8
9.

---

I need to control the message content, in order to use correctly :(
So, it woul be nice if I could enforce the cout to be written immediately in the B application... Or enforce the A application to not append all the cout content.

Example :

Code:

---

int i = 0;
while (i<10)
{
	std::cout << i << std::endl; // Enforce this to be submitted immediately
	i++;
}

---

And the message would be :

Quote:

---

.0.

---

I could have 10 messages, and not just one.

Have you got an idea ?

You can use "cout.flush()" to clear the output buffer, but this won't solve your problem. What you send to cout is a stream --- it doesn't contain any messages.

Application "A" should parse the data it receives and divide it into messages for example by looking for \n. Also you shouldn't assume that you will get a whole message at once --- you might get a part of it.

You need something like:

Code:

---

void Something::readMessages()
{
   buffer.append( myProcess->readAllStandardOutput() ); // note that buffer might contain some data from previous calls
   while( buffer.containsAtLestOneWholeMessage() ) {
      QString msg( buffer.takeFirstMessage() );
      processMessage( msg );
   }
}

---

QString::endsWith() and QString::split() methods might be helpful.

Thanks, this is what I will do...

:)