qtopengl es 3.0 support

Hello and thank you for stopping by.

imx6q
qt 5.7
3.14.52

I have an error in my qtopengl code that has to do with versioning. It seems qt supports opengl es 2.0 without question (for me anyways). I have queried the hardware and here is the results...

Code:

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Opengl vendor 'Vivante Corporation'
renderer 'Vivante GC2000' 
version 'OpenGL ES 3.0 V5.0.11.p7.33433' 
 
12 hardware units can access texture data from vertex and fragment processors
8 hardware units can access texture data from fragment processors
4 hardware units can access texture data from vertex processors
4 hardware units can access texture data from vertex processors

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This means that I should be able to write es 3.0 vertex and fragment shaders and use the es 3.0 APIs to compile such things. Compiling the first shader gives me an error.

Code:

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(2:0) : error : syntax error at 'layout'

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What I have figured out is that the built rootfs has opengl libs for gles2 and i am assuming what I want is gles3. So there is the question(s)...

As my hardware supports 3.0 and it seems qt does support the 3.0 and well beyond functions, how am I supposed to get the correct rootfs files as well as my Qt project on my host to support opengl 3.0?

info::

1) my .pro does have "QT += gui"

2) in a .h file

Code:

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#include <QOpenGLFunctions_3_0>
#include <GLES3/gl3.h>

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3) in a .h file

Code:

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class myClass : public QObject, protected QOpenGLFunctions   // works
class myClass : public QObject, protected QOpenGLFunctions_3_0   // does not work

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4) same .h file without the class definition error

Code:

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class myClass : public QObject, protected QOpenGLFunctions   // works
    protected:
        QOpenGLFunctions_3_0*   m_ogl300Funcs;  // "error: 'QOpenGLFunctions_3_0' does not name a type QOpenGLFunctions_3_0*   m_ogl300Funcs;"

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I am unsure how Qt shows to have all of this opengl version support as well as my hardware but yet I can't use it. Stop teasing, please. 8^)

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Added after 13 minutes:

I found this is the answer...QOpenGLExtraFunctions.

Unless someone has other pointers, I think this is what I am seeing is the answer.