emit a signal

Just a quick one, if I wish to emit a signal from a specific object, I can do like this, right?

emit myObject->mySignal();

Update: There doesn't seem to be any way of making a signal public. Or is there?

You can connect some other signal to it:

Code:

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connect( object1, SIGNAL( someSignal() ), object2,  SIGNAL( someOtherSignal() ) );

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Whenever object1 emits someSignal(), object2 will emit someOtherSignal().

Quote:

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Originally Posted by Morea

Just a quick one, if I wish to emit a signal from a specific object, I can do like this, right?

emit myObject->mySignal();

Update: There doesn't seem to be any way of making a signal public. Or is there?

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Objects can only emit their own signals (including inherited ones), not others'. Signals are protected functions and when the compiler reads your headers, it reads "protected:" rather than "signals:"; short of altering the Qt source code itself, you can't change this. This is covered in "Practical Qt" on page 231.