how to determine geometry of a QFrame

Hi
I have a QFrame *frame A and I want to place a QFrame *helpFrame in it

Code:

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emit displayHelpFunction( frameA, &helpFlag);
	frameA->show();

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and the code in the sub-frame is

Code:

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void HelpFunction::slotDisplayHelpFunction( QFrame *sourceFrame, bool *flag )
{
	 if ( *flag == false)
	{
		helpFrame = new QFrame(  sourceFrame );
		helpFrame->setFrameShape( QFrame::StyledPanel );
		helpFrame->setGeometry( 10, 10, 200, 400 );
		teHelpBox= new QTextEdit( helpFrame );
		teHelpBox->setGeometry(10,10, 180, 380);
		teHelpBox->setPlainText( "Now is the time" );
		helpFrame->show();
		*flag = true;
	}
	else if ( *flag == true )
	{
		*flag = false;
		helpFrame->hide();
	}
}

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and it works fine, with the "helpFrame" in the upper left corner of "frameA", but I want line 7. in terms of the "width" and "height" of frameA.
I don't want to use "spacers" or a "paint" event to get these dimensions if I can help it.

help would be most appreciated.

See QWidget::geometry();
But it is recommended to use layouts instead placing widgets manually.

Quote:

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Originally Posted by marcel

See QWidget::geometry();
But it is recommended to use layouts instead placing widgets manually.

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Thanks, I have given up and gone back to designer.
Going through the discussions, as best I could, I did not find a single reference to "frame.width()" or other such simple, direct, usuable functions. Only in the primary documentations where they are listed.

Thanks anyway
pete

Quote:

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Originally Posted by marcel

But it is recommended to use layouts instead placing widgets manually.

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I think what Marcel was saying is if you would create a layout and make the layout to lie in the main frame. Then add your secondary frame into the layout and work with the layout to manipulate the position it lies in.