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Thread: It seems that Qt does not release unused memory

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  1. #1
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    Default Re: It seems that Qt does not release unused memory

    On linux, what "ps" or "top" have to say?
    Have you tested with other tools at all?

    What if after closing the files you open an application that takes a lot of memory? Does vmrss drops in any way?
    The vmsize is explainable since the virtual memory manager won't adjust the swap every time a process deallocates some memory.

    I tested also with a standard vector and it has the same behaviour, so probably it is a kernel bug/feature.
    I really doubt that a bug of this magnitude could exist in the memory manager.

  2. #2
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    Default Re: It seems that Qt does not release unused memory

    An hour ago I implemented a test program that was allocating 15000 QVector<int> objects, filling them with data and reporting the memory usage through reading /proc/pidnum/status, then deallocating them (by deleting the vectors) and repeating the procedure a few times. I can't show you the sources as running the application rendered my computer unresponsive and I had to make a hard reboot (and the program was stored in /tmp). Nevertheless I monitored the memory usage and it was not what I expected. VmRSS (physical memory) stayed the same during subsequent iterations (which was expected), but VmSize (virtual memory) kept rising during each iteration (which wasn't expected) until it ate all the swap space and froze the system solid. All that means one of two (or more?) things - either I made some stupid mistake that caused memory not to be released properly or there is something wrong with memory management either in Qt or the kernel or.... I don't know where (compiler?)... Or I don't know what VmSize is...
    The app looked essentially like this (+reporting mem usage everywhere):

    Qt Code:
    1. int main(){
    2. QVector<QVector<int>*> vecs;
    3. for(int r=0;r<3;r++){
    4. for(int i=0;i<15000;i++){
    5. QVector<int> *v = new QVector<int>;
    6. for(int j=0;j<10240;j++)
    7. (*v) << 7;
    8. vecs << v; // or was it vecs[i] = *v; ?
    9. }
    10. for(int i=0;i<15000;i++){
    11. delete vecs[i];
    12. }
    13. }
    14. }
    To copy to clipboard, switch view to plain text mode 

    A probable error is not squeezing "vecs" after each iteration, but it shouldn't make it occupy over 2GB of ram (3*15000*sizeof(int) = ~180kB) - at worst it should kill the process on trying to delete an invalid pointer. The funny thing is I have 1,2GB swap + 768MB physical memory in my machine which is less than VmSize was reporting as reserved for the process before the system started freezing.

  3. #3
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    Default Re: It seems that Qt does not release unused memory

    Quote Originally Posted by wysota View Post
    An hour ago I implemented [..]

    Qt Code:
    1. int main(){
    2. QVector<QVector<int>*> vecs;
    3. for(int r=0;r<3;r++){
    4. for(int i=0;i<15000;i++){
    5. QVector<int> *v = new QVector<int>;
    6. for(int j=0;j<10240;j++)
    7. (*v) << 7;
    8. vecs << v; // or was it vecs[i] = *v; ?
    9. }
    10. for(int i=0;i<15000;i++){
    11. delete vecs[i];
    12. }
    13. }
    14. }
    To copy to clipboard, switch view to plain text mode 
    I couldn't understand much on how you extract the info of memory usage but atleast i found this code faulty.
    You initially allocate 15k QVector<int> objects(with 10k int each) and push it to "vecs" vector and you just "delete" the 15k vectors in first pass. Note you aren't clearing the pointers in the "vect" vector.
    In second pass you append 15k QVector<int> objects i.e now there are 30k pointers in vecs and you delete the first 15k "invalid" pointers which seems wrong.

    Probably you could have simplified code like this. (can you try it ? )

    Qt Code:
    1. int main(){
    2. QVector<QVector<int>*> vecs;
    3. for(int r=0;r<3;r++){
    4. for(int i=0;i<15000;i++){
    5. QVector<int> *v = new QVector<int>;
    6. for(int j=0;j<10240;j++)
    7. (*v) << 7;
    8. vecs << v; // or was it vecs[i] = *v; ?
    9. }
    10. qDeleteAll(vecs);
    11. //You missed this clear statement
    12. vecs.clear();
    13. }
    14. }
    To copy to clipboard, switch view to plain text mode 
    Of course you might have just done a cut and paste mistake !
    Last edited by Gopala Krishna; 25th November 2007 at 19:07.
    The biggest difference between time and space is that you can't reuse time.
    -- Merrick Furst

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    Default Re: It seems that Qt does not release unused memory

    qDeleteAll(vecs) is equivalent to for(...) delete vecs[i].

  5. #5
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    Default Re: It seems that Qt does not release unused memory

    Quote Originally Posted by wysota View Post
    qDeleteAll(vecs) is equivalent to for(...) delete vecs[i].
    I know
    I just wanted to say you missed vecs.clear();
    Last edited by Gopala Krishna; 25th November 2007 at 19:52. Reason: spelling error
    The biggest difference between time and space is that you can't reuse time.
    -- Merrick Furst

  6. #6
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    Default Re: It seems that Qt does not release unused memory

    Oh, you meant clear()... No, I didn't miss it. The vector goes out of scope and so it gets cleared anyway. But even if I did miss clear, it would only make my app hold an additional of 45000*sizeof(int*) = ~180kB of memory.

  7. #7
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    Default Re: It seems that Qt does not release unused memory

    Quote Originally Posted by wysota View Post
    Oh, you meant clear()... No, I didn't miss it. The vector goes out of scope and so it gets cleared anyway. But even if I did miss clear, it would only make my app hold an additional of 45000*sizeof(int*) = ~180kB of memory.
    Sorry , but have a look at the code again. vecs is declared before the outermost for loop so it wont get cleared.
    I am not sure how it relates here but deleting an invalid pointer does result in unexpected behavior.
    The biggest difference between time and space is that you can't reuse time.
    -- Merrick Furst

  8. #8
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    Default Re: It seems that Qt does not release unused memory

    Yes, I understand your point. But note that I wrote this wasn't the actual code. In the real app I was probably using the index operator to fill the vector, otherwise delete vecs[i] would have crashed the application during the second iteration of the loop (because of trying to delete an unallocated block of memory). And if you read my original post again, you'll see this line:
    Quote Originally Posted by wysota
    A probable error is not squeezing "vecs" after each iteration, but it shouldn't make it occupy over 2GB of ram (3*15000*sizeof(int) = ~180kB) - at worst it should kill the process on trying to delete an invalid pointer.

  9. #9
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    Default Re: It seems that Qt does not release unused memory

    Quote Originally Posted by wysota View Post
    Yes, I understand your point. But note that I wrote this wasn't the actual code. In the real app I was probably using the index operator to fill the vector, otherwise delete vecs[i] would have crashed the application during the second iteration of the loop (because of trying to delete an unallocated block of memory). And if you read my original post again, you'll see this line:
    That is the reason i put this is in one of the post above
    Of course you might have just done a cut and paste mistake !
    Anyways back to topic
    The biggest difference between time and space is that you can't reuse time.
    -- Merrick Furst

  10. #10
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    Default Re: It seems that Qt does not release unused memory

    There was no cut&paste. I had the program written in /tmp which is a ramdisk. And I had to reboot my computer after running the application. Guess the rest

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