How to delete ui member?

[codeslicer]

So this is the situation: I have created my own custom widget, and it uses 2 separate forms, designed in Designer and defined in the private section of the header file. When I switch between the two forms, I have to delete the objects and layout in the other form, otherwise I get a mess.

I use something like myForm.setupUi() and lster myForm2.setupUi(), but doing that causes problems. So I need to somehow delete the objects created by the setupUi() function. I tried qDeleteAll(children()) but that deleted everything in the widget, not just in the UI part, and I don't want that.

Basically I want to undo the operations of setupUi(). Any ideas? Thanks!

[yogeshm02]

So this is the situation: I have created my own custom widget, and it uses 2 separate forms, designed in Designer and defined in the private section of the header file. When I switch between the two forms, I have to delete the objects and layout in the other form, otherwise I get a mess.

What kind of mess?

[jpn]

The easiest way will be to use separate widgets instead of "this". Using QStackedWidget is also one option.

[codeslicer]

Thanks for answering, but I meant something else I guess...

Check post 20 on this thread: http://www.qtcentre.org/forum/f-qt-p...ins-12013.html

You told me I have to delete the old objects on the form, that's what I have to do. However doing qDeleteAll(children()) deletes everything in that class.

Anyways, thanks in advance! ~codeslicer

[codeslicer]

*BUMP*

jpn if only you could help

[jpn]

However doing qDeleteAll(children()) deletes everything in that class.

This is exactly why I suggested introducing an additional layer. Just allocate a plain wrapper QWidget on which you load the designed form. Then you can simply delete that wrapper widget whenever you want.

[codeslicer]

Sorry for the late reply...

The problem is that I want to use 2 separate, different forms in the same class.

I can't create a "wrapper" widget, is there any way of excluding some objects from the children() list? If I use qDeleteAll(children()) then I want to prevent some of the objects from getting deleted, how would I do that? Can I treat it as a regular QList and use the negative (-) operator to remove certain objects? How would I do that? Would this work:

QObject myPermanentObject;
QObject myPermanentObject2;
...
QObjectList childrenList = children();
childrenList.removeAt(indexOf(myPermanentObject));
childrenList.removeAt(indexOf(myPermanentObject2));
...
qDeleteAll(childrenList);

QObject myPermanentObject;
QObject myPermanentObject2;
...
QObjectList childrenList = children();
childrenList.removeAt(indexOf(myPermanentObject));
childrenList.removeAt(indexOf(myPermanentObject2));
...
qDeleteAll(childrenList);

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Thanks

[jpn]

The problem is that I want to use 2 separate, different forms in the same class.

I can't create a "wrapper" widget

Why would that be?

{
    // setting up a common layout
    layout = new QVBoxLayout(this);
    layout->setMargin(0);
 
    // creating common actions (which are not deleted when changing the form)
    QAction* action = new QAction(this);
    ...
}
 
{
    // setting up form A
    wrapper = new QWidget(this);
    oneUi.setupUi(wrapper);
    layout->addWidget(wrapper);
}
 
{
    // setting up form B
    wrapper = new QWidget(this);
    anotherUi.setupUi(wrapper);
    layout->addWidget(wrapper);
}
 
{
    // cleaning up either form
    delete wrapper;
}

{
    // setting up a common layout
    layout = new QVBoxLayout(this);
    layout->setMargin(0);

    // creating common actions (which are not deleted when changing the form)
    QAction* action = new QAction(this);
    ...
}

{
    // setting up form A
    wrapper = new QWidget(this);
    oneUi.setupUi(wrapper);
    layout->addWidget(wrapper);
}

{
    // setting up form B
    wrapper = new QWidget(this);
    anotherUi.setupUi(wrapper);
    layout->addWidget(wrapper);
}

{
    // cleaning up either form
    delete wrapper;
}

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Or just throw the whole complex idea away and start using QStackedWidget.