QTreeWidgetItem relatiionship

[chaoticbob]

Hi,

I was wondering if there is a way to determine if two QTreewidgetItems are related? I looked through the docs - but I couldn't find a member function of either QTreeWidget or QTreeWidgetItem that could give me what I want.

Thanks.

[JimDaniel]

It depends on what you mean by related. You could call parent() on the two items, if the returned parent pointer is the same, the two items are siblings in the tree, is this what you mean?

[chaoticbob]

Sorry - I should have stated a bit more detail. Basically if given two items (ItemA, ItemD) - I want to be able to determine if ItemD is a child of ItemA.

For instance:

ItemA
  |--ItemB
    |--ItemC
      |--ItemD
ItemE
ItemF
 
ItemD->isChildOf( ItemA ) - this would return true
ItemD->isChildOf( ItemB ) - this would return true
ItemD->isChildOf( ItemC ) - this would return true
ItemD->isChildOf( ItemE ) - this would return false
ItemA->isChildOf( ItemB ) - this would return false

ItemA
  |--ItemB
    |--ItemC
      |--ItemD
ItemE
ItemF

ItemD->isChildOf( ItemA ) - this would return true
ItemD->isChildOf( ItemB ) - this would return true
ItemD->isChildOf( ItemC ) - this would return true
ItemD->isChildOf( ItemE ) - this would return false
ItemA->isChildOf( ItemB ) - this would return false

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....a isParentOf relationship work as well...

Thanks.

[JimDaniel]

Hmm, looks like you might need to keep track of that yourself somehow. Maybe just pass down a list of parent pointers to each new node. Then when you call isChildOf(), it can just query the list for a match? Doesn't seem too elegant, but it might get the job done.

[wysota]

bool isParentOf(QTreeWidgetItem *item1, QTreeWidgetItem *item2){
  if(item2==item1 || item1==0 || item2==0) return false;
  while(item2!=0){
    if(item2==item1) return true;
    item2 = item2->parent();
  }
  return false;
}

bool isParentOf(QTreeWidgetItem *item1, QTreeWidgetItem *item2){
  if(item2==item1 || item1==0 || item2==0) return false;
  while(item2!=0){
    if(item2==item1) return true;
    item2 = item2->parent();
  }
  return false;
}

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[chaoticbob]

Thanks guys.

What wysota suggested works well enough.