Problem with QModelIndex

[spirit]

or you can use this method

QSqlRecord QSqlQueryModel::record ( int row ) const

if (!index.isValid())
   return;
 
int id = qobject_cast<QSqlTableModel *>(index.model())->record(index.row()).value("email.id").toInt();

if (!index.isValid())
   return;

int id = qobject_cast<QSqlTableModel *>(index.model())->record(index.row()).value("email.id").toInt();

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[Kesy]

Thanks a lot man, you are a genius
I used this

...
if (!index.isValid())
   return;
 
QModelIndex idx;
if (!index.column())
   idx = index;
else
   idx = index.model()->index(0, index.row());//0 -- id field
 
int id = index.data(Qt::EditRole).toInt(); 
...

...
if (!index.isValid())
   return;
 
QModelIndex idx;
if (!index.column())
   idx = index;
else
   idx = index.model()->index(0, index.row());//0 -- id field
 
int id = index.data(Qt::EditRole).toInt(); 
...

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and it worked fine.

[spirit]

Thanks a lot man, you are a genius
I used this

...
if (!index.isValid())
   return;
 
QModelIndex idx;
if (!index.column())
   idx = index;
else
   idx = index.model()->index(0, index.row());//0 -- id field
 
int id = index.data(Qt::EditRole).toInt(); 
...

...
if (!index.isValid())
   return;
 
QModelIndex idx;
if (!index.column())
   idx = index;
else
   idx = index.model()->index(0, index.row());//0 -- id field
 
int id = index.data(Qt::EditRole).toInt(); 
...

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and it worked fine.

you are wellcome. but I suggest you to use code from my last post, it is more clear to use (for this task), but in general case this one more preferred.