vector

[wysota]

Then use the const_cast to get rid of "const" or create your arrays on heap:

std::vector <GLfloat*> position;
GLfloat *pos new GLfloat[4];
pos[0] = 0.0;
pos[1] = 1.0;
pos[2] = 0.0;
pos[3] = 0.0;
position.push_back(pos);

std::vector <GLfloat*> position;
GLfloat *pos new GLfloat[4];
pos[0] = 0.0;
pos[1] = 1.0;
pos[2] = 0.0;
pos[3] = 0.0;
position.push_back(pos);

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And remember to delete[] the array when you no longer need it to avoid memory leaks.

Or better yet, make your own class, something like:

struct MyData {
  MyData(GLfloat d1, GLfloat d2, GLfloat d3, GLfloat d4){ d[0] = d1; d[1]=d2; d[2]=d3; d[3]=d4;}
  GLfloat d[4];
  GLfloat & operator[](int i){ return d[i]; }
}
 
std::vector<MyData> pos;
pos.push_back(MyData(0.0, 1.0, 2.0, 3.0));

struct MyData {
  MyData(GLfloat d1, GLfloat d2, GLfloat d3, GLfloat d4){ d[0] = d1; d[1]=d2; d[2]=d3; d[3]=d4;}
  GLfloat d[4];
  GLfloat & operator[](int i){ return d[i]; }
}

std::vector<MyData> pos;
pos.push_back(MyData(0.0, 1.0, 2.0, 3.0));

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[mickey]

thanks, the first example compile, but I'm trying to understand better the thing trying const_cast....but don't compile this...

GLfloat* p = const_cast <GLfloat[4]> (pos);
//const_cast <GLfloat[4]> (pos); //has it sense?
position.push_back(p); //this don't compile

GLfloat* p = const_cast <GLfloat[4]> (pos);
//const_cast <GLfloat[4]> (pos); //has it sense?
position.push_back(p); //this don't compile

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[wysota]

const_cast may not work here or may cause segfaults later on, as you create those arrays on stack and when you push them onto the vector, you'll only push the pointer to the array, which will become invalid when the array goes out of scope. So you should stick with creating those items on heap like in my first example.