problem withh returnPressed

[wysota]

i use regular expression but it is not doing what i want. I want to type the integers bigger than 2 and smaller than 16000, if i am not able to write 1 and 2 how can i type 11 and 12?

How about using QIntValidator?

Besides, you can do it with regular expressions as well, something like this should work:

QRegExp("([3-9][0-9]{0,3})|(2[0-9]{1,3})|(1(([0-6][0-9]{0,3})|([7-9][0-9]{0-2})))");

QRegExp("([3-9][0-9]{0,3})|(2[0-9]{1,3})|(1(([0-6][0-9]{0,3})|([7-9][0-9]{0-2})))");

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[:db:sStrong]

How about using QIntValidator?

Besides, you can do it with regular expressions as well, something like this should work:

QRegExp("([3-9][0-9]{0,3})|(2[0-9]{1,3})|(1(([0-6][0-9]{0,3})|([7-9][0-9]{0-2})))");

QRegExp("([3-9][0-9]{0,3})|(2[0-9]{1,3})|(1(([0-6][0-9]{0,3})|([7-9][0-9]{0-2})))");

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this reg doesnt work i am not able to type anything

[munna]

Why dont you use QIntValidator (as suggested by wysota) and set the range ?

[:db:sStrong]

Why dont you use QIntValidator (as suggested by wysota) and set the range ?

i am using now QIntValidator:

QIntValidator* validator = new QIntValidator( 3,16000 , le );
		validator->setRange(3,16000);
		le->setValidator(validator);
		le->clear();

QIntValidator* validator = new QIntValidator( 3,16000 , le );
		validator->setRange(3,16000);
		le->setValidator(validator);
		le->clear();

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but i am still able to type 1 and 2 i want to have this: >2 and <=16000. the top is good but the bottom value is not good in above code.

[wysota]

i am using now QIntValidator:

QIntValidator* validator = new QIntValidator( 3,16000 , le );
		validator->setRange(3,16000);
		le->setValidator(validator);
		le->clear();

QIntValidator* validator = new QIntValidator( 3,16000 , le );
		validator->setRange(3,16000);
		le->setValidator(validator);
		le->clear();

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but i am still able to type 1 and 2 i want to have this: >2 and <=16000. the top is good but the bottom value is not good in above code.

You can type "1" because to type "1000" you have to be able to type "1" It's just not being accepted as a valid value, but you have to be able to type it in. I think that if the lineedit loses focus, the value will be corrected to a valid one. But maybe it'd be easier for you to use QSpinBox?

[:db:sStrong]

You can type "1" because to type "1000" you have to be able to type "1" It's just not being accepted as a valid value, but you have to be able to type it in. I think that if the lineedit loses focus, the value will be corrected to a valid one. But maybe it'd be easier for you to use QSpinBox?

no i have to use qlineedit in order to clear. the users should only type >2 and <16000 i am going to use focus now lets see what happens..

[wysota]

So tell me something. How do you intend to enter "1111" (which is a valid value) if you forbid to enter a "1"?

[wysota]

Here is my code, try it:

#include <QApplication>
#include <QIntValidator>
#include <QLineEdit>
#include <QDialog>
#include <QVBoxLayout>
 
class MyIntValidator : public QIntValidator {
public:
  MyIntValidator(int l, int t, QObject *p=0) : QIntValidator(l,t,p){}
  void fixup(QString &input) const;
};
 
void MyIntValidator::fixup(QString &input) const {
  int v = input.toInt();
  if(v<bottom()) input = QString::number(bottom());
  if(v>top()) input = QString::number(top());
}
 
int main(int argc, char **argv){
  QApplication app(argc, argv);
  QDialog dlg;
  QVBoxLayout *layout = new QVBoxLayout;
  QLineEdit *le = new QLineEdit(&dlg);
  QLineEdit *other = new QLineEdit(&dlg);
  layout->addWidget(le);
  layout->addWidget(other);
  dlg.setLayout(layout);
  QIntValidator *validator = new MyIntValidator(3,16000, le);
  le->setValidator(validator);
  dlg.show();
  return app.exec();
}

#include <QApplication>
#include <QIntValidator>
#include <QLineEdit>
#include <QDialog>
#include <QVBoxLayout>

class MyIntValidator : public QIntValidator {
public:
  MyIntValidator(int l, int t, QObject *p=0) : QIntValidator(l,t,p){}
  void fixup(QString &input) const;
};

void MyIntValidator::fixup(QString &input) const {
  int v = input.toInt();
  if(v<bottom()) input = QString::number(bottom());
  if(v>top()) input = QString::number(top());
}

int main(int argc, char **argv){
  QApplication app(argc, argv);
  QDialog dlg;
  QVBoxLayout *layout = new QVBoxLayout;
  QLineEdit *le = new QLineEdit(&dlg);
  QLineEdit *other = new QLineEdit(&dlg);
  layout->addWidget(le);
  layout->addWidget(other);
  dlg.setLayout(layout);
  QIntValidator *validator = new MyIntValidator(3,16000, le);
  le->setValidator(validator);
  dlg.show();
  return app.exec();
}

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[:db:sStrong]

Here is my code, try it:

hi I have change ur code according to my situation because i dont use QLineEdit as a class i have qtable and just one COL is made QlineEdit, this is the code:

QWidget* TestTableItem::createEditor() const
{
 
	QLineEdit* le = ( QLineEdit *)(QTableItem::createEditor());
	QString input;
	int v = input.toInt();
 
	if (le)
    { 
		QIntValidator* validator = new QIntValidator( 3,16000 , le );
		if(v > validator->bottom()) input = QString::number(validator->bottom());
	    if(v <validator->top()) input = QString::number(validator->top());
		validator->fixup(input);
		le->setValidator(validator);
 
	}
 
    return le;   
}

QWidget* TestTableItem::createEditor() const
{
	
	QLineEdit* le = ( QLineEdit *)(QTableItem::createEditor());
	QString input;
	int v = input.toInt();
    
	if (le)
    { 
		QIntValidator* validator = new QIntValidator( 3,16000 , le );
		if(v > validator->bottom()) input = QString::number(validator->bottom());
	    if(v <validator->top()) input = QString::number(validator->top());
		validator->fixup(input);
		le->setValidator(validator);

	}

    return le;   
}

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the fixup doesnt work good because i am still able to write 1 and 2

[wysota]

Maybe you didn't notice -- I subclassed QIntValidator. The default implementation of fixup() does nothing so you have to subclass the validator and implement it.

[:db:sStrong]

Maybe you didn't notice -- I subclassed QIntValidator. The default implementation of fixup() does nothing so you have to subclass the validator and implement it.

oke i see i have also subclass QIntvalidator:

class MyIntValidator : public QIntValidator {
 
public:
 
  MyIntValidator(int l, int t, QObject *p=0) : QIntValidator(l,t,p){}
 
  void fixup(QString &input) const;
 
};
 
void MyIntValidator::fixup(QString &input) const {
 
  int v = input.toInt();
 
  if(v<bottom()) input = QString::number(bottom());
 
  if(v>top()) input = QString::number(top());
 
}
 
QWidget* TestTableItem::createEditor() const
{
 
	QLineEdit* le = ( QLineEdit *)(QTableItem::createEditor());
 
	QIntValidator* validator = new QIntValidator(3,16000 , le );
	le->setValidator(validator);
 
    return le;   
}

class MyIntValidator : public QIntValidator {

public:

  MyIntValidator(int l, int t, QObject *p=0) : QIntValidator(l,t,p){}

  void fixup(QString &input) const;

};

void MyIntValidator::fixup(QString &input) const {

  int v = input.toInt();

  if(v<bottom()) input = QString::number(bottom());

  if(v>top()) input = QString::number(top());

}

QWidget* TestTableItem::createEditor() const
{
	
	QLineEdit* le = ( QLineEdit *)(QTableItem::createEditor());
	
	QIntValidator* validator = new QIntValidator(3,16000 , le );
	le->setValidator(validator);

    return le;   
}

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but still its not working, am i doing somthing wrong with subclassing??

[wysota]

QIntValidator* validator = new QIntValidator(3,16000 , le );

QIntValidator* validator = new QIntValidator(3,16000 , le );

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You are still creating an instance of QIntValidator instead of your subclass.

[munna]

I think you need to use QSpinBox.

If you are very particular about QLineEdit then try

QWidget *testTableItem::createEditor() const
{
QLineEdit *lineEdit = new QLineEdit(viewport());
lineEdit->setFrame(false);
//use connect here.
return lineEdit;
}

QWidget *testTableItem::createEditor() const
{
QLineEdit *lineEdit = new QLineEdit(viewport());
lineEdit->setFrame(false);
//use connect here.
return lineEdit;
}

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