Testing qtabwidget tab change.

[shud]

Ok . Let´s go. An example:
I have a widget that insight it has 2 tabwidgets. The tabwidgets are shown at the same time , but only one is active . Ok . In order to actvate the other tabwidget the user must click in the tab of the inactive tabwidget (I want to test this user click ).
Do you understand me ?
It´s simply a widget who has two ore more tabwidgets but only one is active , and if the user want to activate other it must click a tab .

[high_flyer]

Yes, now the problem is clear, what is not clear however is the sense in such a setup.

The tabwidgets are shown at the same time , but only one is active .

So you mean by not active - disabled? does isEnabled() return false for the not active widget?


What is the sense to have a widget be disabled, if you want it to behave just like an enabled widget?
A disabled widget per definition should not respond to mouse and keyboard input.
If all you want is to make it apear as disabled, but not behave as one, you better change the way it is being drawn with or with out focus for example.
The reason is, that a widget set with senEnabled(false) does not receive keyboard and mouse events.

[shud]

It`s difficult to explain the situation, but one widget must be active and the other disable because it must not receive the mouse events. But in order to change the state I need that the disable widget receive a mouse event to activate it.

[high_flyer]

but one widget must be active and the other disable because it must not receive the mouse events. But in order to change the state I need that the disable widget receive a mouse event to activate it.

You are mixing things.
If you need to react to some keyboard/mouse events, then you can't have your widget disabled - So don't disable it.

What you want is a SELECTIVE reaction to events.
For that you can install an event filter for that widget:
see QObject::installEventFilter().