need to run only one instance of application

[navid]

Hello,

before I worked with this delphi code:

function FileInstanceCheck(var mutex : THandle):boolean;
var
        mutexName : array [0..7] of char;
begin
   Result:=false;
   StrPCopy(mutexName ,'anyname');
   mutex := openmutex ( MUTEX_ALL_ACCESS, False, mutexName )  ;
   If ((mutex <> 0) ) then
   begin
    MessageBeep($FFFFFFFF);
    //MyMsgDialog('The application is already running.');
    exit;
   end;
   mutex := createmutex ( nil , true, mutexName);
   Result:=true;
end;

function FileInstanceCheck(var mutex : THandle):boolean;
var
        mutexName : array [0..7] of char;
begin
   Result:=false;
   StrPCopy(mutexName ,'anyname');
   mutex := openmutex ( MUTEX_ALL_ACCESS, False, mutexName )  ;
   If ((mutex <> 0) ) then
   begin
    MessageBeep($FFFFFFFF);
    //MyMsgDialog('The application is already running.');
    exit;
   end;
   mutex := createmutex ( nil , true, mutexName);
   Result:=true;
end;

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now, I look forward to a straightforward Qt code.

regards
navid

[yogeshgokul]

Please refer following link.
http://qt.nokia.com/products/appdev/...gleapplication

[navid]

thanks, i will try new open source one

[yogeshgokul]

please provide me with a free code

Respected Sir,
Would you like to have the code with a double scoop of choco chips icecream?

[dbzhang800]

thanks, i will try new open source one

http://qt.nokia.com/products/appdev/...leapplication/

[vcernobai]

There is another possibility to do what you want:

QLocalSocket socket;
socket.connectToServer(serverName);
if (socket.waitForConnected(500)) return;

m_localServer = new QLocalServer(this);
connect(m_localServer, SIGNAL(newConnection()), this, SLOT(newLocalSocketConnection()));
m_localServer->listen(serverName);

a) You create a QLocalSocket and connect to the server specified by the serverName;
b) Create a QLocalServer and listen for the connections;
c) before starting the application check how much connections you are listening already ... if there is at least one that means you have opened an application and you shouldn't let another one to open