QList of QLists

[m15ch4]

Welcome!

I would like to ask if it is possible to create QList of QLists?
I've tried to do something like this:

QList<QList<int> > myList;

QList<QList<int> > myList;

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but it doesn't compile.

Please help!

[john_god]

I did something like that with some workaround. Just define a class, in that class define a qlist, and then define a qlist of that class. Works like charm

[aamer4yu]

Can you show what compilation error you are getting ?

[vishwajeet.dusane]

Try this

QList<int> myIntList;
 
QList<myIntList> listOFIntList;

QList<int> myIntList;

QList<myIntList> listOFIntList;

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[jano_alex_es]

QList<QList<int> > myList;

This works fine, the problem should be somewhere else. Have you added the include?

[bender86]

typedef QList<YourType> TypeList; // Type definition
...
QList<TypeList> list; // Variable definition.

typedef QList<YourType> TypeList; // Type definition
...
QList<TypeList> list; // Variable definition.

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Or, you could try this way (notice the spaces):

QList< QList<YourType> > list;

QList< QList<YourType> > list;

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[jano_alex_es]

The first blank space is not needed, with the second is enough.

[mirelon]

the second blank is important - if there is two consecutive '>', it is parsed as '>>', which is an operator

[m15ch4]

Hi!

Thanks for your replies. I don't know where the problem was but now everything works. I'm using that version:
QList<QList<int> > myList;

[*Baby*]

It seems only to work if there is a space between brackets.

This works:
QList<QList<int> > myList;
QList< QList<int> > myList;

This doesn't work:
QList<QList<int>> myList;

[anda_skoa]

mirelon already explained this. you need a space between the two > characters, otherwise the >> is seen as operator>>().

I do believe, however, that with C++11 this is parsed correctly

Cheers,
_