Synchronizing "Show XXX window" action checked state with some window's visibility

[abey]

Hello,

In my soft, I've got a windows and a menu item and related action to control the window's visibility. The action is checkable, so I can do

connect(action, SIGNAL(toggled(bool)), window, SLOT(setVisible(bool)));

connect(action, SIGNAL(toggled(bool)), window, SLOT(setVisible(bool)));

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Is there an easy way to do the opposite -- ie. have the toggled state of the action updated whenever the visibility of the window changes?

TIA,
Antoine

[Lykurg]

Yes: QWidget::setHidden().

Edit: Ehm, forget about it, misread


Edit2: And now the answer: There is no signal but an event: QWidget::showEvent()/QEvent::Show/QEvent::Hide

[abey]

So the window's parent (say my QMainWindow's subclass) could intercept this event and change the action accordingly, provided that the main windows is somehow the parent of the windows whose visibility we want to track. Is that correct?

[Lykurg]

Your main window mustn't be the parent. I can think of two options: a) install an event filter on your widgets you want to watch or create an abstract class which must be inherited by your windows. There catch the show and hide event and emit custom signals. Then you can use signal and slots as you are used to.