Nested signals and slots

[vishva]

hai friends,

I am suffering the following problem in my application.

Code:

Header file:

class Sample: public QDialog
{

private slots:

void fun1();

void fun2();

};

cpp file:

Sample::Sample
{

connect(&object,SIGNAL(clicked()),this,SLOT(fun1() ));
}

void Sample::fun1()
{
connect(&object,SIGNAL(clicked()),this,SLOT(fun2() ));
}

void Sample::fun2()
{

//
// to run some instruction here
}


Ok, run this program,

First time,
Main widget( Clicked) -> fun1() -> clicked -> fun2() then return to main widget
Here ,its work fine.

Second time,

Main widget( Clicked) -> fun1() -> clicked -> fun2() then again call fun2() , then return to main widget
3rd time,
the function2 called 3 times.

Nth time ,

The function2 called n times.


i.e,
the last function ( fun2() ) called number of times automatically ( current + prev ).


Can you tell me ,what is the problem in nested signals and slots ?

[jpn]

Can you tell me ,what is the problem in nested signals and slots ?

The problem is that you are forming a new connection every time the fun1() slot is called. The old connections naturally remain unless you disconnect them.

I'm not sure what are you trying to achieve, but maybe you need something like this:

void Sample::fun1()
{
    disconnect(&object,SIGNAL(clicked()),this,SLOT(fun1() ));
    connect(&object,SIGNAL(clicked()),this,SLOT(fun2() ));
}

void Sample::fun1()
{
    disconnect(&object,SIGNAL(clicked()),this,SLOT(fun1() ));
    connect(&object,SIGNAL(clicked()),this,SLOT(fun2() ));
}

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[vishva]

hi jpn,

i sloved that problem using disconnect() in fun2(). so it works fine.

Thanks