How to generate an array of random numbers

[Zlatomir]

You can use qrand

[baluk]

Hi,

I have tried using the qrand() but I can't able to get the desired output. I want to generate a random set with non-repeatable alphabets. I have tried like this

int array[] = {65,66,67,68,69,70,71,72};
   qsrand(time(0));
    for(i=0;i < SequenceCount; i++)
    {
        int j = (qrand() % SequenceCount );
        qDebug() << array[j];
    }

int array[] = {65,66,67,68,69,70,71,72};
   qsrand(time(0));
    for(i=0;i < SequenceCount; i++)
    {
        int j = (qrand() % SequenceCount );
        qDebug() << array[j];
    }

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But in the output I see some repeatable numbers.

[wysota]

You mean you want to have a random permutation of the array?

#include <algorithm>
 
int array[] = {65,66,67,68,69,70,71,72};
std::shuffle(array, array+8);

#include <algorithm>

int array[] = {65,66,67,68,69,70,71,72};
std::shuffle(array, array+8);

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[baluk]

Yes I need the same functionality U have given me. But the statement

std::shuffle(array, array+8);

is not recognized. it says "shuffle" is not a member of the std.

then I used

std::rand_shuffle(array, array);

std::rand_shuffle(array, array);

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but it is giving me some extra garbage values along with the result. like

EBGCAFHD Ã…
@|%

.

[Zlatomir]

The function name is random_shuffle and you need to include <algorithm>

[wysota]

If you print something to the console, it has to end with \0. This is basic C/C++ knowledge.