Convert from QAction to QWidget

[duck182]

Hi,

i'm getting the following error message while compiling:

error C2664: 'QTest::mouseClick' : cannot convert parameter 1 from 'QAction *' to 'QWidget *'

error C2664: 'QTest::mouseClick' : cannot convert parameter 1 from 'QAction *' to 'QWidget *'

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This is my coding:

QMenuBar* mb = pWidget->findChild<QMenuBar *>("menubar");
QAction* fileAction = mb->findChild<QAction *>("File");
QAction* newProject = fileAction->findChild<QAction *>("Create New Project...");
QTest::mouseClick( newProject, Qt::LeftButton );

QMenuBar* mb = pWidget->findChild<QMenuBar *>("menubar");
QAction* fileAction = mb->findChild<QAction *>("File");
QAction* newProject = fileAction->findChild<QAction *>("Create New Project...");
QTest::mouseClick( newProject, Qt::LeftButton );

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Two questions:
1) I know that mouseClick expects a QWidget, but in the tutorial the use e.g. QLineEdit so i think this should work with QAction, too?!
2) Is there another possibility to get the children of an object? I think it's weird to get the children from a top-object this way..

kind regards

[wysota]

but in the tutorial the use e.g. QLineEdit so i think this should work with QAction, too?!

No, because QLineEdit inherits QWidget and QAction does not.

Call QAction::trigger() instead of simulating a click.

[duck182]

So it should look like this?

newProject->trigger();

newProject->trigger();

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[wysota]

if(newProject)
  newProject->trigger();
else
  qFatal("Action newProject not found");

if(newProject)
  newProject->trigger();
else
  qFatal("Action newProject not found");

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[duck182]

Hi,

mh okay I did not get the correct objects..

But I'm not able to get QAction::trigger() working..
The QMenuBar contains a QMenu. The QMenu contains a QAction. But this QAction has no objectName.
So how do I get the correct pointer to the QAction-item?

QMenuBar* mb = pWidget->findChild<QMenuBar *>("menubar"); // works
QMenu* fileMenu = mb->findChild<QMenu *>("menuMenu");      // works
 
// Now i would like to get the pointer to the QAction. 
QAction* newProject = fileMenu ->findChild<QAction *>("Create New Project..."); // this won't work because the QAction-object has no name

QMenuBar* mb = pWidget->findChild<QMenuBar *>("menubar"); // works
QMenu* fileMenu = mb->findChild<QMenu *>("menuMenu");      // works

// Now i would like to get the pointer to the QAction. 
QAction* newProject = fileMenu ->findChild<QAction *>("Create New Project..."); // this won't work because the QAction-object has no name

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The goal is to simulate a mouseclick on this QAction.

[nightghost]

You can set the objectname with QObject::setObjectName()

[duck182]

I'm testing a complete application so I'm not able to give object names to these QActions.

[wysota]

Use QMenu::actionAt() or QWidget::actions().

[duck182]

Okay, thank you so far.

Now i get all actions and the submenu-objects correctly.
One questions remains
How can I call a specific QAction? At the moment I'm iterating the QList<QAction *> to get the ations.. If there are more than one I have to select one (which is obviously possible by comparing the text of these actions). But how can I choose one without iterating?

[wysota]

If your action is the fifth added to the widget, you can call:

menu->actions().at(4);

menu->actions().at(4);

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etc.

[duck182]

Oh okay, but not via the text-property or sth equal?

[wysota]

You can iterate over available actions and check their text if you want.