[pyqt]Event - catch only Qt.Key_Delete

[kosset]

Hello!

I would like to change behavior of Key_Delete for QTableWidget, but because of using Designer I don't want to make any changes in py file with form. So instead of reimplementing QTableWidget, I do something like this:

class MyForm(QtGui.QMainWindow):
  def __init__(self, parent=None):
      QtGui.QWidget.__init__(self, parent)
      self.ui = Ui_MainWindow()
      self.ui.setupUi(self)
 
      self.ui.tableWidget.__class__.keyPressEvent = self.test
 
  def test(self,event):
      if event.key() == Qt.Key_Delete:
          print "test"
 
      return QTableWidget.keyPressEvent(self, event)

class MyForm(QtGui.QMainWindow):
  def __init__(self, parent=None):
      QtGui.QWidget.__init__(self, parent)
      self.ui = Ui_MainWindow()
      self.ui.setupUi(self)
  
      self.ui.tableWidget.__class__.keyPressEvent = self.test

  def test(self,event):
      if event.key() == Qt.Key_Delete:
          print "test"
  
      return QTableWidget.keyPressEvent(self, event)

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The problem is that I don't know how to keep original behavior of other keys than Qt.Key_Delete. I have already changed last line like this:

return QtGui.QTableWidget.keyPressEvent(self, event)
return QtGui.QTableWidget.event(self, event)

return QtGui.QTableWidget.keyPressEvent(self, event)
return QtGui.QTableWidget.event(self, event)

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but it doesn't work.

[svarti]

return QtGui.QTableWidget.keyPressEvent(self.ui.tableWidget, event)

return QtGui.QTableWidget.keyPressEvent(self.ui.tableWidget, event)

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[anda_skoa]

Or you could use an event filter, see QObject::eventFilter()

Cheers,
_