read output data

[wysota]

Assuming proper byte ordering and length of integer as 32 bits:

unsigned char message[50]; // your message here
int status;
int statusFiscal;
char text[41];
memcpy(&status, message, 4);
memcpy(&statusFiscal, message+5);
memcpy(text, message+10, 40);
text[40] = '\0';
printf("status: %d\nfiscal: %d\ntext:%s\n", status, statusFiscal, text);

unsigned char message[50]; // your message here
int status;
int statusFiscal;
char text[41];
memcpy(&status, message, 4);
memcpy(&statusFiscal, message+5);
memcpy(text, message+10, 40);
text[40] = '\0';
printf("status: %d\nfiscal: %d\ntext:%s\n", status, statusFiscal, text);

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[KillGabio]

I think your answer to my "problem" is correct, the thing is that i`m working with an emulator of a printer so that might be the problem of "extrange output". I`m receiving the warning: too many arguments for format while trying to execute:

printf ("Respuesta: %s", buffer);

this is something i should ignore?

[wysota]

The code seems correct. At least if you're using a regular compiler. What is the type of "buffer"? Is this your actual code? In your first post you have two %s marks in the line concerning "buffer".

[KillGabio]

Yes i had two separators, i was just trying to test what happened. The code posted is a method of a class. As private variables I have:

int handler;
    char buffer[512];                
    char comando[512];

int handler;
    char buffer[512];                
    char comando[512];

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