Remove a QLayout from QGridLayout

[grosem]

Happy new Year

I have a QGridLayout and added some QLayouts, which I want to remove now:

leftBox->addLayout(itemList[itemID]);
leftBox->removeItem(itemList[itemID]);
itemList[itemID]->setParent(0);

leftBox->addLayout(itemList[itemID]);
leftBox->removeItem(itemList[itemID]);
itemList[itemID]->setParent(0);

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leftBox is my QGridLayout
itemList is a QList which contains Points of QHBoxLayout. The adding of the layouts is no problem.
In this example I want to remove them immediatly. removeItems() puts the removed layouts to the same place (left top corner of the leftBox). I actually thought this is as the added Layouts have still leftBox as parent. So I set another parent, which was useless.

So how can I remove this layouts without deleting the removed layout as I want to add it later again?

[jpn]

You would have to hide the removed widgets. Removing a widget from a layout only means that the widget is no more managed by the layout and so it will stay in the upper left corner unless it is re-parented. I do personally find it a good idea to avoid dynamically changing layouts as much as possible and use for example a stacked widget or layout instead. Of course they don't fit to all situations. In this case you would most likely have to disable the layout during the changes to avoid the flicker, at least if there are several changes in a row.

[grosem]

Stacked Layout is no alternative for me, but thanks for your advise, it worked.

EDIT: But I got this problem:

QLayout::addChildLayout: layout "" already has a parent

QLayout::addChildLayout: layout "" already has a parent

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I did

topBox->removeItem(itemList[itemID]);
		itemList[itemID]->hide();

topBox->removeItem(itemList[itemID]);
		itemList[itemID]->hide();

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After this I tried to add it at another Layout.

I thought by removing the item (which is a layout) I can add it somewhere else. But it seems it still keeps its parent!?

[grosem]

The only possibility I found is to make a new Item with the same value and delete the old one. But this can't be the right solution, can it?

[jpn]

QLayout::addChildLayout: layout "" already has a parent

Sounds like you are missing the

itemList[itemID]->setParent(0);

itemList[itemID]->setParent(0);

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which you had earlier..?

Could you describe the GUI you are building? Maybe there's another way for constructing something similar?

[grosem]

Sounds like you are missing the

itemList[itemID]->setParent(0);

itemList[itemID]->setParent(0);

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which you had earlier..?

Could you describe the GUI you are building? Maybe there's another way for constructing something similar?

I tried this too. But got a

X Error: BadWindow (invalid Window parameter) 3
Major opcode: 25 (X_SendEvent)
Resource id: 0x20000ad

Well, I have three frames, which have Items. These items are a QHBoxLayout which has 2 QLabels and a QSpinBox. The user should be able to drag these items between the three frames.

At first I tried the QItemView approach, but I wasn't able to do it the way I wanted.

I know my new approach using Layouts isn't the right one, but it is much simplier for me. Just the thing of removing does not work yet.

Thanks for your help

[jpn]

Yeah, the suggestion would have been using item views..

[grosem]

I never thought this reuse of Layouts would be a problem

[grosem]

I don't get it:

leftBox->addLayout(protoItem2);
leftBox->removeItem(protoItem2);
protoItem2=0;
delete protoItem2;

leftBox->addLayout(protoItem2);
leftBox->removeItem(protoItem2);
protoItem2=0;
delete protoItem2;

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Why is there still the layout in the leftBox??? Even more weird is that the added layout had two QLabels, but only one is still visible (the one with a QPixmap). leftBox->update() changes nothing.

[jpn]

leftBox->addLayout(protoItem2);
leftBox->removeItem(protoItem2);
protoItem2=0;
delete protoItem2; // <--- same as "delete 0;"

leftBox->addLayout(protoItem2);
leftBox->removeItem(protoItem2);
protoItem2=0;
delete protoItem2; // <--- same as "delete 0;"

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leftBox->addLayout(protoItem2);
leftBox->removeItem(protoItem2);
delete protoItem2; // delete first
protoItem2=0; // then set the pointer to 0

leftBox->addLayout(protoItem2);
leftBox->removeItem(protoItem2);
delete protoItem2; // delete first
protoItem2=0; // then set the pointer to 0

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[grosem]

ok, that's of course true, but unfortunatly that does not change something.

I did following: The Items I add to the QGridLayout are from a class derived from QHBoxLayout. I added two QLabels to this class and added them in the Constructor to the QHBoxLayout. I actually though by deleting the object of the class the two QLabels would be deleted too. But apparently that's not the case. Having added this in the destructor

~Item(){delete myName; delete myIcon;}

~Item(){delete myName; delete myIcon;}

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it works.

Seems very dirty for me