Signal-slots connection problem.

[impeteperry]

I found this in the documentation

void QAbstractButton::click () [slot]

Performs a click.

All the usual signals associated with a click are emitted as appropriate. If the button is checkable, the state of the button is toggled.

This function does nothing if the button is disabled.

so went back to my non-detigner program for button click.

connect( pb5, 	SIGNAL( clicked() ), this, SLOT( slotPb5() ) );

connect( pb5, 	SIGNAL( clicked() ), this, SLOT( slotPb5() ) );

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Then went to the implementation

void dlgMain::slotPb5()
{
	QStringList temp;
	QString  k;
 
	if( pb5->text() == "~" ) return;
	emit setButtonActionList( 5, "5" );

void dlgMain::slotPb5()
{
	QStringList temp;
	QString  k;

	if( pb5->text() == "~" ) return;
	emit setButtonActionList( 5, "5" );

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so why not in designer? In the "Signnl Slot Editor" i have:
" pb5 clicked Pb5 click() "
and in my program I have

#include <QtGui>
 
#include "pmform.h"
 
PmForm::PmForm(QWidget *parent)
	: QWidget(parent)
{
	ui.setupUi(this);
 
	ui.leZone->setText("leZone");
}
 
void PmForm::Pb5()
{
	ui.leZone->setText("This is what I want");
}

#include <QtGui>

#include "pmform.h"

PmForm::PmForm(QWidget *parent)
	: QWidget(parent)
{
	ui.setupUi(this);

	ui.leZone->setText("leZone");
}

void PmForm::Pb5()
{
	ui.leZone->setText("This is what I want");
}

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it compiles ok, but when I run it and click on the "Pb5" button I get

pete@peteBox:~/Desktop/PM-designer/pm$ ./pm
Segmentation fault
pete@peteBox:~/Desktop/PM-designer/pm$

At least I am getting a connection form inside designer to my "pmform.cpp"
Now, how do I get rid of the segmentation fault?

Thanks, Help would be most appreciatei.