When is timeout signal fired (Qtimer)

[aamir_azad]

Is timeout() signal fired when I explicitly stop the timer? If yes, what should I do to prevent it from being called?
Thanks in advance.

[ChrisW67]

No, the timeout() signal is issued when the timer has expired and the program has returned to the Qt event loop. Calling stop() immediately kills the timer.

[aamir_azad]

Here is my code. I want that the msg box appears ONCE if the cursor stays inside the widget for two sec continuously.But when i move the cursor in (for 1sec) and then out, and again in for two sec, the message box appears for Random no of time..
what am i doing wrong??
Custom1.h

#ifndef CUSTOM1_H
#define CUSTOM1_H
#include<QPushButton>
#include<QTimer>
 
    class Custom1 : public QPushButton
    {
            Q_OBJECT
 
        public:
            explicit Custom1(QWidget* parent = 0) : QPushButton(parent)
            {
            connect(this, SIGNAL(clicked()), this, SLOT(display_in()));
            connect(this, SIGNAL(pressed()), this, SLOT(display_out()));
            }
            ~Custom1() {}
 
        protected:
            void enterEvent(QEvent*);
            void leaveEvent(QEvent*);
 
        public slots:
            void display_in();
            void display_out();
            void display();
 
    };
 
 
 
#endif // CUSTOM1_H

#ifndef CUSTOM1_H
#define CUSTOM1_H
#include<QPushButton>
#include<QTimer>

    class Custom1 : public QPushButton
    {
            Q_OBJECT

        public:
            explicit Custom1(QWidget* parent = 0) : QPushButton(parent)
            {
            connect(this, SIGNAL(clicked()), this, SLOT(display_in()));
            connect(this, SIGNAL(pressed()), this, SLOT(display_out()));
            }
            ~Custom1() {}

        protected:
            void enterEvent(QEvent*);
            void leaveEvent(QEvent*);
           
        public slots:
            void display_in();
            void display_out();
            void display();

    };



#endif // CUSTOM1_H

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Custom1.cpp

#include "custom1.h"
#include<QTimer>
#include<QMessageBox>
 
QTimer *my_timer = new QTimer();
 
void Custom1::enterEvent(QEvent*)
{
    Q_EMIT clicked();
connect(my_timer, SIGNAL(timeout()), this, SLOT(display()));
 
  my_timer->setSingleShot(true);
   my_timer->start(2000);
 
}
 
void Custom1::leaveEvent(QEvent*)
{
 
    if (my_timer->isActive())
    {
         my_timer->stop();
    }
 
 
    Q_EMIT pressed();
}
 
void Custom1::display_in()
{
    setText("CURSOR IN");
}
 
void Custom1::display_out()
{
    setText("CURSOR OUT");
}
 
void Custom1::display()
{
 
    a++;
    setText(QString::number(a));
 
 
 
 
  QMessageBox msg;
   msg.setText("hi");   // <--- THIS MESSAGE BOX APPEARS SOME RANDOM NO OF TIMES... WHY??
   msg.exec();
}

#include "custom1.h"
#include<QTimer>
#include<QMessageBox>

QTimer *my_timer = new QTimer();

void Custom1::enterEvent(QEvent*)
{
    Q_EMIT clicked();
connect(my_timer, SIGNAL(timeout()), this, SLOT(display()));

  my_timer->setSingleShot(true);
   my_timer->start(2000);

}

void Custom1::leaveEvent(QEvent*)
{

    if (my_timer->isActive())
    {
         my_timer->stop();
    }


    Q_EMIT pressed();
}

void Custom1::display_in()
{
    setText("CURSOR IN");
}

void Custom1::display_out()
{
    setText("CURSOR OUT");
}

void Custom1::display()
{
  
    a++;
    setText(QString::number(a));
   
     
      

  QMessageBox msg;
   msg.setText("hi");   // <--- THIS MESSAGE BOX APPEARS SOME RANDOM NO OF TIMES... WHY??
   msg.exec();
}

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[wysota]

Please provide a minimal compilable example reproducing the problem.

[Lesiok]

First of all timer signal is emmited AFTER 2 sec. If in this 2 sec Custom1::enterEvent(QEvent*) is called a few times timer signal is connected to display many times. Secondly, you never disconnect timer signal from display slot.

[aamir_azad]

Thanks Lesiok!!!

got the mistake!!!

Now its working