<vector>

[shad]

seems you forget about copy ctors.

You are right, the behaviour of vector is implementation defined. That's the gcc 3.4.2 output:

ctor 0
copy ctor 1
copy ctor 2
copy ctor 3
dtor 4
ctor 5
copy opt 6
dtor 7
dtor 8
dtor 9
dtor 10

#include <vector>
#include <iostream>
 
class Test
{
  static int _no;
public:
  Test()
  {
    std::cout << "ctor " << _no++ << std::endl;
  }
  Test(const Test&)
  {
    std::cout << "copy ctor " << _no++ << std::endl;
  }
  ~Test()
  {
    std::cout << "dtor " << _no++ << std::endl;
  }
  Test& operator= (const Test&)
  {
    std::cout << "copy opt " << _no++ << std::endl;
  }
};
 
int Test::_no = 0;
 
int main()
{
   std::vector<Test> x;
   x.resize(3);
 
   x[ 15 ] = Test();
   return 0;
}

#include <vector>
#include <iostream>

class Test
{
  static int _no;
public:
  Test()
  {
    std::cout << "ctor " << _no++ << std::endl;
  }
  Test(const Test&)
  {
    std::cout << "copy ctor " << _no++ << std::endl;
  }
  ~Test()
  {
    std::cout << "dtor " << _no++ << std::endl;
  }
  Test& operator= (const Test&)
  {
    std::cout << "copy opt " << _no++ << std::endl;
  }
};

int Test::_no = 0;

int main()
{
   std::vector<Test> x;
   x.resize(3);

   x[ 15 ] = Test();
   return 0;
}

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