How to forward primary key of selected row QTableView

[Sashabn]

Hi everyone, i am new in programming world, so please forgive me if i ask stupid question....
I was make my Sql connection to database and use QSqlTableModel to fill QSqlTableView. This is my code:
ui->setupUi(this);
QSqlTableModel *model=new QSqlTableModel(this);
model->setTable("baza");
model->select();
ui->tableRadnici->setModel(model);
ui->tableRadnici->setEditTriggers(QAbstractItemView::NoEditTriggers );
and table "baza":
mysql> describe baza;
+----------+--------------+------+-----+---------+-------+
| Field | Type | Null | Key | Default | Extra |
+----------+--------------+------+-----+---------+-------+
| id | int(14) | NO | PRI | NULL | |
| name | varchar(100) | YES | | NULL | |
| lastname | varchar(100) | YES | | NULL | |
| sector | varchar(100) | YES | | NULL | |
+----------+--------------+------+-----+---------+-------+
4 rows in set (0.00 sec)

My question is how can i forward id of table row to some function, example if i do double click on field name to forward value of field ID to function
void DialogListaRadnika:n_tableRadnici_activated(const QModelIndex &index);

I was looking for solution for about mount, and i fail with that, so please help me.
Thanks

[anda_skoa]

You have the model index of whatever cell got activated.
You can use the row information to get an index of the first column, which holds your id.

Cheers,
_

[Sashabn]

Thanks for quick replay
I was solve this problem by this syntax
ui->tableRadnici->model()->data(ui->tableRadnici->model()->index(index.row(),0)).toString();
where ui->tableRadnici is my QTableView in my form.
Cheers