QtTableWidget to fire of a function

[anda_skoa]

I'm having trouble finding info on itemClicked.
I saw this:
[signal] void QTableWidget::itemDoubleClicked(QTableWidgetItem * item)

There is also QTableWidget::itemClicked().

But how do I implement it? Say I have a function:

def myPrint():
print ('hooray')

How do I get itemClicked to fire this function?

You connect this function to the signal

Secondly... What is QTableWidgetItem * item? What kind of info does it have?

That is a pointer to a QTableWidgetItem with the name "item".
In Python that will likely be an object reference to a QTableWidgetItem object.

Is there a benefit to using the signals and slot mechanism rather than the code style.
So example:
self.PushButton1.clicked.connect(myPrint()) VS ui.connect(PushButton1, Signal(clicked), Slot ...)
any benefit using one over the other?

I guess the second one is more like it is done in C++, but the first one will probably be easier for other Python people to understand.

How do I call the myPrint function using Signal/Slot method on Pushbutton1? Or can I?

I am afraid I don't understand, you have the connect right there, no?

Cheers,
_

[Nfrancisj]

I think I'm confusing myself. Hahaha I'm watching Qt C++ vids on YouTube and trying to find the equivalent in PyQt/PySide.
I apologize.
Let me start again:
I have a function. Same one above, myPrint()

Using the non signal method, this works:
ui.pushbutton1.clicked.connect(myPrint())

Now I'm trying to see if I can get it using Signals&Slots.
This doesn't work.
connect(ui.pushbutton1, SIGNAL(clicked()), ui.pushbutton1, SLOT(myPrint()))
Neither does this...
connect(ui.pushbutton1, SIGNAL(clicked()), myPrint())

What is the correct syntax?

Thanks!

[anda_skoa]

I
Using the non signal method, this works:
ui.pushbutton1.clicked.connect(myPrint())

If that works, why not use it?

I
Now I'm trying to see if I can get it using Signals&Slots.
This doesn't work.
connect(ui.pushbutton1, SIGNAL(clicked()), ui.pushbutton1, SLOT(myPrint()))

myPrint is not a function of pushbutton1, right?

I
Neither does this...
connect(ui.pushbutton1, SIGNAL(clicked()), myPrint())

There is no SLOT() in this line.

You might also have to specify "self" as the receiver object.

Cheers,
_

[Nfrancisj]

If that works, why not use it?
_

There are something's easier in slot method. I'm just trying to learn all the possibles just to be flexible.

There is no SLOT() in this line.
_

That's what I thought when I saw this: @time 13:32, Line 23
http://youtu.be/0vvb7Kv59qA


Then I tried it in my script, and it didn't work. I even duplicated the setup he has. I used QtDesigner instead of writing it out,but I can't seem to understand what he is doing different to make line 23 work.

Hahaha, there's another guy in Spain, I'm trying to find his video again, who does Signals and slots in a different way also. He uses some weird syntax.

By the way, I'm not doing any projects or anything. just studying QT in my spare time. and I thank you very much, again, for helping me understand things.

cheers!

[Nfrancisj]

I figured it out. I need to write it this way:

QtCore.QObject.connect(self.myButton, QtCore.SIGNAL('clicked()'), myFunction)

The clouds have cleared, and now everything hooks up well.