open a window according to the type chosen in mainwindow

[rahma_sassi]

Hello
I work on an application under qt 5,
The user must first choose whether it is a doctor or patient or administrator
la2.PNG
After another window will be opened to connect or register
mainwindow.PNG
If it clicks on join I want another window will be opened but depending on the type of user.
mainwindow.cpp
join_connect.cpp


So please what can I do to I open a window according to the type chosen in mainwindow

[anda_skoa]

C++ offers two language constructs to execute different code depending on some condition or value

The "if-else" statement https://en.wikipedia.org/wiki/Condit...2.80.93else.29
And the "switch" statement https://en.wikipedia.org/wiki/Switch_statement

You can likely find some C++ tutorials online to learn how to use these.

Cheers,
_

[rahma_sassi]

Good evening,
Thank you for your help
But when I use if and else if an error appears when compiling the program
C:\Users\LENOVO\Desktop\projet c++\code-sql\smart health v1\smart_health\mainwindow.h:26: error: 'void MainWindow:n_pushButton_3_clicked()' cannot be overloaded
void on_pushButton_3_clicked();
^
and an other :
C:\Users\LENOVO\Desktop\projet c++\code-sql\smart health v1\smart_health\mainwindow.h:19: error: with 'bool MainWindow:n_pushButton_3_clicked()'
bool on_pushButton_3_clicked();
^
This is because the on_pushButton_3_clicked () function is private and type void not bool.
Here is my mainwindow.h
mainwindow.h

[d_stranz]

I think anda_skoa means something like this:

// pseudocode
void MainWindow::on_pushButton_3_clicked()
{
    switch ( userType )
    {
        case User:
             showUserWindow();
             break;
 
        case Doctor:
             showDoctorWindow();
             break;
 
        case Administrator:
             showAdminWindow();
             break;
 
        default:
             // error - no such user type
             break;
    }
}

// pseudocode
void MainWindow::on_pushButton_3_clicked()
{
    switch ( userType )
    {
        case User:
             showUserWindow();
             break;

        case Doctor:
             showDoctorWindow();
             break;

        case Administrator:
             showAdminWindow();
             break;

        default:
             // error - no such user type
             break;
    }
}

To copy to clipboard, switch view to plain text mode 

Obviously, your code will store the "userType" based on the previous button the user clicked.

By the way, "pushButton_3" is a pretty bad name for a variable. A year from now, when you have to fix something in this code, will you remember which GUI button is the one named "pushButton_3" in the code? You'd probably have a much easier job if it were named "connectButton" or "joinButton" instead.

[anda_skoa]

C:\Users\LENOVO\Desktop\projet c++\code-sql\smart health v1\smart_health\mainwindow.h:26: error: 'void MainWindow:n_pushButton_3_clicked()' cannot be overloaded
void on_pushButton_3_clicked();
^
and an other :
C:\Users\LENOVO\Desktop\projet c++\code-sql\smart health v1\smart_health\mainwindow.h:19: error: with 'bool MainWindow:n_pushButton_3_clicked()'
bool on_pushButton_3_clicked();
^
This is because the on_pushButton_3_clicked () function is private and type void not bool.

You have two functions with the same name, in C++ that's called an overload.
Overloaded functions need to have different arguments, different return type is not enough.

I would suggest you look into a basic C++ tutorial first before continuting.

Cheers,
_