Get index of QValueListIterator

[jacek]

no...i must do it

Judging from the error message, yes.

[zlatko]

Understand...So i can't get in other way position(index) of curent iterators item ?

[jacek]

Understand...So i can't get in other way position(index) of curent iterators item ?

This should work:

for( int i = 0, GroupList::const_iterator itGr = gl_GroupList.constBegin(); itGr != gl_GroupList.constEnd(); ++i, ++itGr) {
   int  m_nCurrKey = i; 
   //... 
}

for( int i = 0, GroupList::const_iterator itGr = gl_GroupList.constBegin(); itGr != gl_GroupList.constEnd(); ++i, ++itGr) {
   int  m_nCurrKey = i; 
   //... 
}

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[zlatko]

No it was my first solution...Actually like this becouse yours cant be compiled

int i;
for( i = 0, GroupList::const_iterator itGr = gl_GroupList.constBegin(); itGr != gl_GroupList.constEnd(); ++i, ++itGr) {
   int  m_nCurrKey = i;

int i;
for( i = 0, GroupList::const_iterator itGr = gl_GroupList.constBegin(); itGr != gl_GroupList.constEnd(); ++i, ++itGr) {
   int  m_nCurrKey = i;

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But the i think must be more elegant way to solve it...Now i see that its imposible

[jacek]

But the i think must be more elegant way to solve it...Now i see that its imposible

Either you use iterators or access your data by index. Usually there is no need to do both.

You can always do this:

const int size = gl_GroupList.size();
for( int i = 0; i < size; ++i ) {
   int  m_nCurrKey = i; 
   //...
   // gl_GroupList[i] 
   //...
};

const int size = gl_GroupList.size();
for( int i = 0; i < size; ++i ) {
   int  m_nCurrKey = i; 
   //...
   // gl_GroupList[i] 
   //...
};

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[zlatko]

Yes it can be more flexibility solution
thanks