How to get a QString from a file (use regular expression)

[fengtian.we]

I try it (QRegExp::capturedTexts() ) ,

find one ....

[high_flyer]

what do you mean?
in your last post count() returned 3...
Better if you show your code, and not only explain the end effect.

[fengtian.we]

QString str="my name is bob,bobis good boy,i lick bob<";
QRegExp reg("bob");
reg.indexIn(str);
QStringList list=reg.capturedTexts();
qDebug() << list.count(); // output : 1

[high_flyer]

After a closer reading, it turns out capturedTexts() is not the right method you are looking for:

Some regexps can match an indeterminate number of times. For example if the input string is "Offsets: 12 14 99 231 7" and the regexp, rx, is (\d+)+, we would hope to get a list of all the numbers matched. However, after calling rx.indexIn(str), capturedTexts() will return the list ("12", "12"), i.e. the entire match was "12" and the first subexpression matched was "12". The correct approach is to use cap() in a loop.

[fengtian.we]

I'm read the Qt Assistant yesterday, I thinks should be :

QString str="bob's msn is aa@g.com,and bob's email is qq@aaaa.com.cn :)";
	QRegExp reg("[A-z0-9_\.-]+@[A-z0-9\.]+");
 
	int count=str.count(reg);
	int from=0;
	int in=0;
	QStringList rs;
 
	for(int i=0;i<count;i++)
	{
		in=reg.indexIn(str,from);
		rs.append(reg.cap(0));
		from=in+rs.value(i).size();
	}
 
 
	qDebug() << rs.count();   //output 4(aa@g.com,a@g.com,qq@aaaa.com.cn,q@aaaa.com.cn)
 
	qDebug() << rs.value(0);                        //output "aa@g.com"
	qDebug() << rs.value(1);                       //output "qq@aaaa.com.cn"
	qDebug() << rs.value(2);                        //output ""
	qDebug() << rs.value(3);                        //output ""

QString str="bob's msn is aa@g.com,and bob's email is qq@aaaa.com.cn :)";
	QRegExp reg("[A-z0-9_\.-]+@[A-z0-9\.]+");

	int count=str.count(reg);
	int from=0;
	int in=0;
	QStringList rs;

	for(int i=0;i<count;i++)
	{
		in=reg.indexIn(str,from);
		rs.append(reg.cap(0));
		from=in+rs.value(i).size();
	}


	qDebug() << rs.count();   //output 4(aa@g.com,a@g.com,qq@aaaa.com.cn,q@aaaa.com.cn)

	qDebug() << rs.value(0);                        //output "aa@g.com"
	qDebug() << rs.value(1);                       //output "qq@aaaa.com.cn"
	qDebug() << rs.value(2);                        //output ""
	qDebug() << rs.value(3);                        //output ""

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how about this is that ok?

and please check my regular expressions"[A-z0-9_\.-]+@[A-z0-9\.]+".

[fengtian.we]

OK!!!! Thank you everyone!

this is my way:

QString str="bob's msn is aaa@g.com,and bob's email is qq@aaaa.com.cn :)";
	QRegExp reg("[A-z0-9_\.-]+@[A-z0-9\.]+");
 
	int startPos=0;
	int mailPos=0;
	QStringList rs;
 
	while(true)
	{
		mailPos=reg.indexIn(str,startPos);
		if(mailPos<0)
		{
			break;
		}
		rs.append(reg.cap(0));
		startPos=mailPos+rs.last().size();
	}
 
	qDebug() << rs.count();                     // 2
	qDebug() << rs.value(0);                   // "aaa@g.com"
	qDebug() << rs.value(1);                   // "qq@aaaa.com.cn"

QString str="bob's msn is aaa@g.com,and bob's email is qq@aaaa.com.cn :)";
	QRegExp reg("[A-z0-9_\.-]+@[A-z0-9\.]+");

	int startPos=0;
	int mailPos=0;
	QStringList rs;

	while(true)
	{
		mailPos=reg.indexIn(str,startPos);
		if(mailPos<0)
		{
			break;
		}
		rs.append(reg.cap(0));
		startPos=mailPos+rs.last().size();
	}

	qDebug() << rs.count();                     // 2
	qDebug() << rs.value(0);                   // "aaa@g.com"
	qDebug() << rs.value(1);                   // "qq@aaaa.com.cn"

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haha