QMessageBox error

[Salazaar]

Hi. I've got a problem. I have a piece of code:

int ret = QMessageBox::Information(this, tr("Speed Units Converter"),
                   tr("You can't convert value to the same unit"),
                   QMessageBox::Ok | QMessageBox::Default);
                   if (ret == QMessageBox::Ok)
                   {
                   return false;
                   }

int ret = QMessageBox::Information(this, tr("Speed Units Converter"),
                   tr("You can't convert value to the same unit"),
                   QMessageBox::Ok | QMessageBox::Default);
                   if (ret == QMessageBox::Ok)
                   {
                   return false;
                   }

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And I reach error that Information cannot be used as a function
Regards

[jpn]

QMessageBox::information() with lower case i.

[Salazaar]

Thanks, now's all right. But there's another problem. Here's piece of code

if (beaufortBox->isChecked() && knotBox_2->isChecked())
          {
                               convertDialog->setWindowTitle("Converting value from Beaufort to Knot");// this is error line
                               toLabel->setText("Knot(s)");
                               displayConvertDialog();                             
          }

if (beaufortBox->isChecked() && knotBox_2->isChecked())
          {
                               convertDialog->setWindowTitle("Converting value from Beaufort to Knot");// this is error line
                               toLabel->setText("Knot(s)");
                               displayConvertDialog();                             
          }

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And I've got error, that expected primary expression before -> token. What is this problem about? Regards

[jpn]

Where is "convertDialog" declared?

[Salazaar]

it is form created by designer, I was subclassing this form.