simple console application does ot finish

[szisziszilvi]

Hi,

I'm creating a console application. I've created it in the Qt Creator with New File or Project (...) and I've changed the main just like this:

#include <QtCore/QCoreApplication>
#include <iostream>
 
int main(int argc, char *argv[])
{
    QCoreApplication a(argc, argv);
 
 
    std::cout << "hello" << std::endl;
 
     return a.exec();
}

#include <QtCore/QCoreApplication>
#include <iostream>

int main(int argc, char *argv[])
{
    QCoreApplication a(argc, argv);


    std::cout << "hello" << std::endl;

     return a.exec();
}

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The only problem around this is that when I run it it does not seem to finish. I have to terminate the program "roughly" by switching off the popping console window or running it from a command promt using Ctrl+C. In the Creator I get the message:
F:\(mypath)\myproject-build-desktop\release\myproject.exe exited with code -1073741510


I've found this thread:
http://www.qtcentre.org/threads/3620...-order-of-code
but it does not seem to work for me or I'm not using it nice.

So at last the question is:
How to finish a qt console application correctly?
In the future it has to happen at specific eventy, most likely at a keyboard press, now how to achieve that? (I've seen that once somewhere, but I cannot find it anymore.)

Szilvi

[Lykurg]

With exec() you start an event loop you have to quit using quit() for your application you can simply write

return 0;

return 0;

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[szisziszilvi]

Yes, I see for this very simple application return 0 should work. The question is how to use these exec-quit properly? If the main ends with the line "return a.exec();" then where should the quit function be called? The default code that is generated by the creator is just this:

#include <QtCore/QCoreApplication>
 
    int main(int argc, char *argv[])
    {
    QCoreApplication a(argc, argv);
 
    return a.exec();
    }

#include <QtCore/QCoreApplication>
     
    int main(int argc, char *argv[])
    {
    QCoreApplication a(argc, argv);
     
    return a.exec();
    }

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As I guess (because everybody says "use quit") this assumes the programmer will add the a.quit() somewhere - but where?

[Lykurg]

As soon as you create a widget and show it, Qt will handle it. Otherwise you have to quit the (empty) gui loop.

[Lesiok]

This application will end after 5 seconds :

#include <QtCore/QCoreApplication>
 
    int main(int argc, char *argv[])
    {
    QCoreApplication a(argc, argv);
 
    QTimer::singleShot(5000,&a,SLOT(quit())); 
    return a.exec();
    }

#include <QtCore/QCoreApplication>
     
    int main(int argc, char *argv[])
    {
    QCoreApplication a(argc, argv);
    
    QTimer::singleShot(5000,&a,SLOT(quit())); 
    return a.exec();
    }

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