Numerous functions with similar names/actions

[kramed]

jpn, I have changed my code to what you suggested and it compiles but unforunately I am setgfaulting on an invalid call to show(); Do the object names need to be named like an array (ie, label[1]) or do they stay the same (ie, label1). I have created the UI in designer and it wont let me input square brackets into the object name. If I must name the object names as arrays I would have to modifiy the .ui manually.

Is there anyway to determine the exact line that the program is failing on, gdb's output was:

Program received signal SIGSEGV, Segmentation fault.
[Switching to Thread -1223964144 (LWP 19874)]
0x0804bd1b in QWidget::show (this=0x0) at /usr/include/qt4/QtGui/qwidget.h:463
463 inline void show() { setVisible(true); }

[jpn]

jpn, I have changed my code to what you suggested and it compiles but unforunately I am setgfaulting on an invalid call to show(); Do the object names need to be named like an array (ie, label[1]) or do they stay the same (ie, label1). I have created the UI in designer and it wont let me input square brackets into the object name.

This happens because you have an uninitialized array of pointers. You must assign sensible values to pointers in the array. Unfortunately there is no way to tell designer to assign to a custom array. What you can do about it is to assign them by hand:

setupUi(this);
ass_labels[0] = ass_label1;
ass_labels[1] = ass_label2;
...

setupUi(this);
ass_labels[0] = ass_label1;
ass_labels[1] = ass_label2;
...

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Is there anyway to determine the exact line that the program is failing on, gdb's output was:

Try command "bt" aka backtrace.

[kramed]

Thank you very much for the assistance, you have been a great help indeed.